Historically, the SAT score has unknown distribution with a mean of 1510 points and a standard deviation of340.5 points.Let X be the SAT score of a randomly selected student and let X be the average SAT score of a randomsample of size 14.Explain why the Central Limit Theorem cannot be used.the original population is normally distributed although the sample size is small (n<30)the sample size is small (n<30) and the distribution of the original population is unknownthe original population is normally distributed and the sample is large (n>30)O the sample size is large (n>30) although the distribution of the original population is unknown

Central limit theorem: If the size of the samples taken from the population are sufficiently…

Answered: Historically, the SAT score has unknown…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Do the part d, e, f and g only tha
SAT scores in one state is normally distributed with a mean of 1403 and a standard deviation of 64. Suppose we randomly pick 56 SAT scores from that state.a) Find the probability that one of the scores in the sample is greater than 1404.P(X>1404)P(X>1404) = b) Find the probability that the average of the scores for the sample of 56 scores is greater than 1404.P(¯¯¯X>1404)P(X¯>1404) = Round each answer to at least 4 decimal places.
please state the approximate distribution of the sample mean
The overhead reach distances of adult females are normally distributed with a mean of 197.5 cm and a standard deviation of 8 cm.Find the probability that a individual distance 207.50 cm.Find the probability that a mean for 20 randomly selected distances is greater than 195.30cm.Why can the normal distribution be used in part B even though the sample size does not exceed 30
A population has an average of 200 with a standard deviation of 25. A random sample of 64 items is chosen. What is the smallest interval that will contain 91.46% of the sample means? Standard error (3 decimal places) = Z = Larger sample mean (1 decimal place) = Smaller sample mean (1 decimal place) =
population has a mean of 200 and a standard deviation of 50. Suppose a simple random sample of size 100 is selected and is used to estimate u. a. What is the probability that the sample mean will be within 25 of the population mean? b. What is the probability that the sample mean will be within@10 of the population mean? L(Ctrl) -
Suppose that a researcher is interested in estimating the mean systolic blood pressure, u, of executives of major corporations. He plans to use the blood pressures of a random sample of executives of major corporations to estimate u. Assuming that the standard deviation of the population of systolic blood pressures of executives of major corporations is 26 mm Hg, what is the minimum sample size needed for the researcher to be 99% confident that his estimate is within 4 mm Hg of u? Carry your intermediate computations to at least three decimal places. Write your answer as a whole number (and make sure that it is the minimum whole number that satisfies the requirements). (If necessary, consult a list of formulas.)
The central limit theorem states that the sampling distribution of sample means has a mean equal to the population -- mean mean mean divided by the population standard deviation mean divided by the population standard deviation standard deviation standard deviation standard deviation divided by the square root of N.
CNNBC recently reported that the mean annual cost of auto insurance is 954 dollars. Assume the standard deviation is 271 dollars. You take a simple random sample of 96 auto insurance policies.Find the probability that a single randomly selected value is less than 969 dollars.P(x<969)=P(x<969)= Find the probability that a sample of size n=96n=96 is randomly selected with a mean less than 969 dollars.P(¯x<969)=P(x¯<969)= Enter your answers as numbers accurate to 4 decimal places.
SAT scores in one state is normally distributed with a mean of 1532 and a standard deviation of 200. Suppose we randomly pick 50 SAT scores from that state. a) Find the probability that one of the scores in the sample is less than 1492. P(X < 1492) = b) Find the probability that the average of the scores for the sample of 50 scores is less than 1492. P(X < 1492) =
Assume that the weights of trout in a river are normally distributed. You randomly catch and weigh 20 such trout. The mean weight from your sample is 7.3 lb with a standard deviation of 0.9 lb. Test the claim that the mean weight of trout in this river is greater than 7 lb at a significance level of 0.01. Be sure to clearly identify your work, using appropriate notation at each step of the process, and summarize your final result in a complete sentence.
According to the Center for Disease Control and Prevention (CDC), the mean life expectancy in 2015 for Hispanic females was 84.3 years. Assume that the standard deviation was 15 years, as suggested by the Bureau of Economic Research. The distribution of age at death,X, is not normal because it is skewed to the left. Nevertheless, the distribution of the mean x¯, in all possible samples of size ? is approximately normal if ? is large enough, by the central limit theorem. Let x¯ be the mean life expectancy in a sample of 100 Hispanic females. Determine the interval centered at the population mean ? such that 95% of sample means x¯ will fall in the interval. Give your answers precise to one decimal.

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