Hi i need to carry out a propagation of Young's modulus to find the overall error for it. I have the readings and I have calculated the overall error for E (for Cantilever beam) but I'm not sure if it is correct. Pls could it be checked or could I have some help with it please. Thanks.
Hi i need to carry out a propagation of Young's modulus to find the overall error for it. I have the readings and I have calculated the overall error for E (for Cantilever beam) but I'm not sure if it is correct. Pls could it be checked or could I have some help with it please. Thanks.
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Hi i need to carry out a propagation of Young's modulus to find the overall error for it. I have the readings and I have calculated the overall error for E (for Cantilever beam) but I'm not sure if it is correct. Pls could it be checked or could I have some help with it please. Thanks.
![Calculate overall error for E:
Relative uncertainity:
E= FL
31S
ΔΕ
SAL
1. 4. 20-8-20
第一。
E
4€ = 4/1
AE_AF_AS
E F
مام
AF = 0.01
F
for Cantilever Beam:
=
Absolore Uncertainity =
Δδ 0.01 = 3.24 x 10-³ (Error / uncertaining in measurement of deflection)
S
3.09
Relative Uncertaining
= 0.01 -(-3.24x10-³) = 0.01324
Absolute Uncertainity
for Simply - Supported Beam:
X 168 061-0972 = 22.251
= 0.01324 x 168 061-0972
100
Relative uncertai
100
ncertainity x measured value
}
€ = 168 061.0972 MPa](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F54d98749-4362-4fae-b3ce-7878d3a0f5e9%2Fdf120cc0-dc28-43e5-9317-17183117bd00%2F8525uhu_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Calculate overall error for E:
Relative uncertainity:
E= FL
31S
ΔΕ
SAL
1. 4. 20-8-20
第一。
E
4€ = 4/1
AE_AF_AS
E F
مام
AF = 0.01
F
for Cantilever Beam:
=
Absolore Uncertainity =
Δδ 0.01 = 3.24 x 10-³ (Error / uncertaining in measurement of deflection)
S
3.09
Relative Uncertaining
= 0.01 -(-3.24x10-³) = 0.01324
Absolute Uncertainity
for Simply - Supported Beam:
X 168 061-0972 = 22.251
= 0.01324 x 168 061-0972
100
Relative uncertai
100
ncertainity x measured value
}
€ = 168 061.0972 MPa
![Error propagation (from lective notes)
E = f(L, F, b, S, [F/Smax])
For a Cantilever beam:
E = FL³
31Smax
2
Equation: (62)² + (6 A)² + (588)² + (doc)"
f
=
F=2N L=360mm S = 3,09mm
E = 2 × (360³)
=168 061. 0972 MPa
3x59.85x3.09
Uncelhaining onb = ±0.001
uncertainity on L = ± 0.05 Em or ± 0.5mm
on](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F54d98749-4362-4fae-b3ce-7878d3a0f5e9%2Fdf120cc0-dc28-43e5-9317-17183117bd00%2Fcae1s41_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Error propagation (from lective notes)
E = f(L, F, b, S, [F/Smax])
For a Cantilever beam:
E = FL³
31Smax
2
Equation: (62)² + (6 A)² + (588)² + (doc)"
f
=
F=2N L=360mm S = 3,09mm
E = 2 × (360³)
=168 061. 0972 MPa
3x59.85x3.09
Uncelhaining onb = ±0.001
uncertainity on L = ± 0.05 Em or ± 0.5mm
on
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