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Hi can you answer the following question: Using the data from questions 3 and 4, calculate the experimental value of Ka for this unknown acid using an ICE table.   The data from question 3 and 4 are attached. Thank you! Aditional information if needed: unknown acid concentration: 0.042mol/L unknown acid volume: 0.25L NaOH concentration: 0.1M NaOH volume at the equivalence point: 0.105L Initial [H30+] is 5.01 x 10-4 mol/L

Hi can you answer the following question: Using the data from questions 3 and 4, calculate the experimental value of Ka for this unknown acid using an ICE table.   The data from question 3 and 4 are attached. Thank you! Aditional information if needed: unknown acid concentration: 0.042mol/L unknown acid volume: 0.25L NaOH concentration: 0.1M NaOH volume at the equivalence point: 0.105L Initial [H30+] is 5.01 x 10-4 mol/L

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Hi can you answer the following question:

Using the data from questions 3 and 4, calculate the experimental value of Ka for this unknown acid using an ICE table.

 

The data from question 3 and 4 are attached. Thank you!

Aditional information if needed:

unknown acid concentration: 0.042mol/L

unknown acid volume: 0.25L

NaOH concentration: 0.1M

NaOH volume at the equivalence point: 0.105L

Initial [H30+] is 5.01 x 10-4 mol/L



3| Given: V of unknown acid = 0.25L V of 0.1M NaOH = 0.105L HA (ag) + NaOH (aq) -> NaA (aq) + H20) meaning its a 1:1 reaction Vi*Sı = V2*S2 can be used C unknown acid = (0.105L x 0.1mol/L) / (0.25L) = 0.042mol/L :. initial acid concentration is 0.042mol/L Given: Initial pH = 3.30 pH = -log(H30"] can be used [H30*] = 10PH M [H30*] = 103.30M [H30°] = 5.0119 x 10“ M .. Initial [H30*] is 5.01 x 104 mol/L ल
Transcribed Image Text:3| Given: V of unknown acid = 0.25L V of 0.1M NaOH = 0.105L HA (ag) + NaOH (aq) -> NaA (aq) + H20) meaning its a 1:1 reaction Vi*Sı = V2*S2 can be used C unknown acid = (0.105L x 0.1mol/L) / (0.25L) = 0.042mol/L :. initial acid concentration is 0.042mol/L Given: Initial pH = 3.30 pH = -log(H30"] can be used [H30*] = 10PH M [H30*] = 103.30M [H30°] = 5.0119 x 10“ M .. Initial [H30*] is 5.01 x 104 mol/L ल
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