2. Answer the questions for the acid below: a) Write the acid dissociation constant, Ka, expression for the reaction: b) If [A] = 0.030 M, [H3O+] = 0.010 M, and [HA] = 0.5 M, what is the value of Ka? c) If another acid, HB, has a Ka value of 1.0 x 10-10, which acid is stronger? HA or HB? Why? HA(aq) + H₂O(1)→ H30+ (aq) + A¯ (aq)

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### Acid Dissociation Constant (Ka) Calculation and Comparison

**Problem Statement:**

**2. Answer the questions for the acid below:**

\[ \text{HA(aq)} + \text{H}_2\text{O(l)} \rightleftharpoons \text{H}_3\text{O}^+ \text{(aq)} + \text{A}^- \text{(aq)} \]

**a) Write the acid dissociation constant, \( K_a \), expression for the reaction:**

\[ K_a = \frac{[\text{H}_3\text{O}^+][\text{A}^-]}{[\text{HA}]} \]

**b) If \([\text{A}^-] = 0.030 \, \text{M}\), \([\text{H}_3\text{O}^+] = 0.010 \, \text{M}\), and \([\text{HA}] = 0.5 \, \text{M}\), what is the value of \( K_a \)?**

Using the expression for \( K_a \), substitute the given concentrations:

\[ K_a = \frac{(0.010 \, \text{M})(0.030 \, \text{M})}{0.5 \, \text{M}} = \frac{0.0003 \, \text{M}^2}{0.5 \, \text{M}} = 0.0006 \]

So, the value of \( K_a \) is 0.0006.

**c) If another acid, HB, has a \( K_a \) value of \( 1.0 \times 10^{-10} \), which acid is stronger? HA or HB? Why?**

Since the strength of an acid is directly proportional to the value of its \( K_a \), the acid HA is stronger than HB. The \( K_a \) value of HA (0.0006) is greater than the \( K_a \) value of HB (\(1.0 \times 10^{-10}\)), indicating that HA dissociates to a greater extent in solution than HB.
Transcribed Image Text:### Acid Dissociation Constant (Ka) Calculation and Comparison **Problem Statement:** **2. Answer the questions for the acid below:** \[ \text{HA(aq)} + \text{H}_2\text{O(l)} \rightleftharpoons \text{H}_3\text{O}^+ \text{(aq)} + \text{A}^- \text{(aq)} \] **a) Write the acid dissociation constant, \( K_a \), expression for the reaction:** \[ K_a = \frac{[\text{H}_3\text{O}^+][\text{A}^-]}{[\text{HA}]} \] **b) If \([\text{A}^-] = 0.030 \, \text{M}\), \([\text{H}_3\text{O}^+] = 0.010 \, \text{M}\), and \([\text{HA}] = 0.5 \, \text{M}\), what is the value of \( K_a \)?** Using the expression for \( K_a \), substitute the given concentrations: \[ K_a = \frac{(0.010 \, \text{M})(0.030 \, \text{M})}{0.5 \, \text{M}} = \frac{0.0003 \, \text{M}^2}{0.5 \, \text{M}} = 0.0006 \] So, the value of \( K_a \) is 0.0006. **c) If another acid, HB, has a \( K_a \) value of \( 1.0 \times 10^{-10} \), which acid is stronger? HA or HB? Why?** Since the strength of an acid is directly proportional to the value of its \( K_a \), the acid HA is stronger than HB. The \( K_a \) value of HA (0.0006) is greater than the \( K_a \) value of HB (\(1.0 \times 10^{-10}\)), indicating that HA dissociates to a greater extent in solution than HB.
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