5.98 At 25°C, the standard enthalpy of formation of HF(aq) is−320.1 kJ/mol; of OH−(aq), it is −229.6 kJ/mol; of F−(aq),it is −329.1 kJ/mol; and of H2O(l), it is −285.8 kJ/mol.(a) Calculate the standard enthalpy of neutralization ofHF(aq): HF(aq) + OH¯(aq)·F (aq) + H,O(1)(b) Using the value of –56.2 kJ as the standard enthalpychange for the reactionH*(aq) + OH¯(aq) – H2O(1)calculate the standard enthalpy change for the reactionHF(aq) H*(aq) + F´(aq)

Given a)Reaction is HF (aq) +OH-(aq) → F-(aq)+H2O(l) Standard enthalpy of formation of ∆Hf…

Answered: HF(aq) + OH¯(aq)· F (aq) + H,O(1) (b)…

Introduction to Chemical Engineering Thermodynamics

8th Edition

ISBN:9781259696527

Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart

Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart

Chapter1: Introduction

Section: Chapter Questions

Problem 1.1P

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5.98 At 25°C, the standard enthalpy of formation of HF(aq) is
−320.1 kJ/mol; of OH−

(aq), it is −229.6 kJ/mol; of F−
(aq),
it is −329.1 kJ/mol; and of H2O(l), it is −285.8 kJ/mol.
(a) Calculate the standard enthalpy of neutralization of
HF(aq):

HF(aq) + OH¯(aq)·
F (aq) + H,O(1)
(b) Using the value of –56.2 kJ as the standard enthalpy
change for the reaction
H*(aq) + OH¯(aq) – H2O(1)
calculate the standard enthalpy change for the reaction
HF(aq) H*(aq) + F´(aq)

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