HERMODYNAMICS: Given the following hypothetical thermochemical equations: 2QJ3 (g) + 3Q2X (g) → 4Q2 (g) + 3J2X (I) 4QJ3 (g) + 3X2 (g) → 2Q2 (g) + 6J2X (1) Calculate the value of AH (in kJ) for the reaction: AH = -1098.5 kJ AH = -1505.8 kJ Q2 (g) + ½ X2 (g) → Q2X (g) (Round off final answer to ONE decimal place)

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Q: 6) CO(g) + 2 H2(g) CH3OH(1) For this reaction, AH° = -128.1 kilojoules AHF (kJ mol¯1) | AG,° (kJ…

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A: To calculate  the  delta H° (in kJ) for the hypothetical reaction:

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A: To fill the blank boxes with calculated values