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Here is the graph that represents a function f. Which equation represents the function? A. f(x) = |x| – 1 B. g(x) = [x – 1| C. H(x) = [x + 1| D. j(x) = \x| + 1

Here is the graph that represents a function f. Which equation represents the function? A. f(x) = |x| – 1 B. g(x) = [x – 1| C. H(x) = [x + 1| D. j(x) = \x| + 1

College Algebra (MindTap Course List)
College Algebra (MindTap Course List)
12th Edition
ISBN:9781305652231
Author:R. David Gustafson, Jeff Hughes
Publisher:R. David Gustafson, Jeff Hughes
Chapter4: Polynomial And Rational Functions
Section4.2: Polynomial Functions
Problem 83E
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Hello: Please see attached. The answer is wrong. The answer is B (according to answer key). Can someone explain why B is the correct answer? Thank you very much!

Statement Here is the graph that represents a function f. Which equation represents the function? A. f(x) = [x| – 1 B. g(x) = |x – 1| C. h(x) = [x + 1| D. jx) = |x| + 1 Solution Transcribed Image Text: Statement Here is the graph that represents a function f. 4 Which equation represents the function? 5432A. f(x) = |x| -1B. gix) = x - 1| C. hộ = |x+ 1| D. jóx) = x| + 1 Solution N to Expert Solution Step 1 We can find the answer as below Step 2 Solution: We know the values of modulus function stay positive for all the values of x, Here in the given graph of the function f(x) is positive for every value of x. So its a Modulus functio. Now at x = 1, f(x) = 0 Hence h(x) = Ix – 1| is the required function whose graph is given.
Transcribed Image Text:Statement Here is the graph that represents a function f. Which equation represents the function? A. f(x) = [x| – 1 B. g(x) = |x – 1| C. h(x) = [x + 1| D. jx) = |x| + 1 Solution Transcribed Image Text: Statement Here is the graph that represents a function f. 4 Which equation represents the function? 5432A. f(x) = |x| -1B. gix) = x - 1| C. hộ = |x+ 1| D. jóx) = x| + 1 Solution N to Expert Solution Step 1 We can find the answer as below Step 2 Solution: We know the values of modulus function stay positive for all the values of x, Here in the given graph of the function f(x) is positive for every value of x. So its a Modulus functio. Now at x = 1, f(x) = 0 Hence h(x) = Ix – 1| is the required function whose graph is given.
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