Here is the code of bubble sort. Its run time complexity is 8(n²). Change the code in a way so that its time complexity is 8(n) for the best-case scenario. You have to explain how you have achieved the 8(n) for the best-case scenario in a comment block of your code. def bubbleSort(arr): for i in range(len(arr)-1): for j in range(len(arr)-i-1): if arr[j] > arr[j+1]: arr[j], arr[j+1] = arr[j+1], arr[j] Input 1: 5 32145 Input 2: 6 5 10 15 20 25 30 Output 1: 12345 Output 2: 5 10 15 20 25 30 For the input 2, your code should run at 8(n). Please note, you have to take the input from an input3.txt file, and show the output in an output3.txt file.

Here is the code of bubble sort. Its run time complexity is 8(n²). Change the code in a way so that its time complexity is 8(n) for the best-case scenario. You have to explain how you have achieved the 8(n) for the best-case scenario in a comment block of your code. def bubbleSort(arr): for i in range(len(arr)-1): for j in range(len(arr)-i-1): if arr[j] > arr[j+1]: arr[j], arr[j+1] = arr[j+1], arr[j] Input 1: 5 32145 Input 2: 6 5 10 15 20 25 30 Output 1: 12345 Output 2: 5 10 15 20 25 30 For the input 2, your code should run at 8(n). Please note, you have to take the input from an input3.txt file, and show the output in an output3.txt file.

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Concept explainers

Merge sort

Merge Sort recursively sorts a given collection of numbers or elements by using the divide and conquer strategy in less time. It is one of the most used algorithms, with the worst-case time complexity of O (n log n). It was invented by John Von Neumann. The algorithm continuously divides an array into sub-arrays until each sub-array consists of a single element. It then merges those sub-arrays to produce a sorted array.

Question

Here is the code of bubble sort. Its run time complexity is 8(n²). Change the code in a
way so that its time complexity is 8(n) for the best-case scenario.
You have to explain how you have achieved the 8(n) for the best-case scenario in a
comment block of your code.
def bubbleSort(arr):
for i in range(len(arr)-1):
for j in range(len(arr)-i-1):
if arr[j] > arr[j+1]:
arr[j], arr[j+1] = arr[j+1], arr[j]
Input 1:
5
32145
Input 2:
6
5 10 15 20 25 30
Output 1:
12345
Output 2:
5 10 15 20 25 30
For the input 2, your code should run at 8(n).
Please note, you have to take the input from an input3.txt file, and show the
output in an output3.txt file.

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So how fast is the merge sort? Does it depend on the type of array? We saw with some of our previous sorts that it depended on the initial array. For example, an Insertion sort was much faster for a nearly sorted array. In this exercise, you are given the Sorter class, which contains a static mergeSort method that takes an int array and length as an input. You are also given the SortTester class which has three static methods for creating 3 different types of arrays. For this test, create one of the three arrays, then take a start time using System.currentTimeMillis(). Next, run the array through the mergeSort method in the Sorter class. Finally, record the end time and print out the results. Repeat this for the other two array types. Sample Output Random Array: ** Results Hidden ** Almost Sorted Array: ** Results Hidden ** Reverse Array: ** Results Hidden **
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