Here I have numbèred the atoms in the imidazole ring for you. Notice that the N at position #4 at the top of the ring does not have a lone pair outside the ring. To satisfy Huckel's Rule, that lone pair has to be inside the ring, meaning it would not be available for hydrogen bonding. histidine NH NH2 serine но- но. 3 INH2 active site 2 H- regenerated R. If the imidazole ring were rotated 180 degrecs, so that #4 is down and # 2 is up, then the hydrogen bond with the H on the serine hydroxyl group would not happen. But a hydrogen bond between the O of serinc and the H on N # 4 could happen. There must be something else keeping the imidazole ring oriented as shown. The P domain is arranged so that there is an aspartate side chain just above the imidazole ring. What is the charge of the aspartate side chain at physiologic pH? (Please look up the pKa on the internet) +1 O neutral

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Chapter1: Chemical Foundations
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Here I have numbèred the atoms in the imidazole ring for you. Notice that the N at position #4 at the
top of the ring does not have a lone pair outside the ring. To satisfy Huckel's Rule, that lone pair has to
be inside the ring, meaning it would not be available for hydrogen bonding.
histidine
NH
NH2
serine
но-
но.
NH2
active site
2 H-
regenerated
If the imidazole ring were rotated 180 degrees, so that #4 is down and #2 is up, then the hydrogen
bond with the H on the serine hydroxyl group would not happen. But a hydrogen bond between the O
of serine and the H on N #4 could happen. There must be something else keeping the imidazole ring
oriented as shown.
The P domain is arranged so that there is an aspartate side chain just above the imidazole ring. What is
the charge of the aspartate side chain at physiołogic pH? (Please look up the pKa on the internet)
O+1
O neutral
Transcribed Image Text:Here I have numbèred the atoms in the imidazole ring for you. Notice that the N at position #4 at the top of the ring does not have a lone pair outside the ring. To satisfy Huckel's Rule, that lone pair has to be inside the ring, meaning it would not be available for hydrogen bonding. histidine NH NH2 serine но- но. NH2 active site 2 H- regenerated If the imidazole ring were rotated 180 degrees, so that #4 is down and #2 is up, then the hydrogen bond with the H on the serine hydroxyl group would not happen. But a hydrogen bond between the O of serine and the H on N #4 could happen. There must be something else keeping the imidazole ring oriented as shown. The P domain is arranged so that there is an aspartate side chain just above the imidazole ring. What is the charge of the aspartate side chain at physiołogic pH? (Please look up the pKa on the internet) O+1 O neutral
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