Here are summary statistics for randomly selected weights of newborn girls: n= 168, x= 28.2 hg, s=7.3 hg. Construct a confidence interval estimate of the mean. Use a 95% confidence level. Are these results verydifferent from the confidence interval 26.4 hg < µ< 29.4 hg with only 20 sample values, x= 27.9 hg, and s = 3.1 hg?.....What is the confidence interval for the population mean u?|hg <µ< \ hg (Round to one decimal place as needed.)Help me sove thisView an examplePrintMacBook888escF5F6F7F3F4&241247QWETYtabAGH.caps lockCVвshiftaltcommand#3

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MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Here are summary statistics for randomly selected weights of newborn girls: n= 240, x= 31.8 hg, s=7.9 hg. Construct a confidence interval estimate of the mean. Use a 99% confidence level. Are these results very different from the confidence interval 29.1 hg < u< 34.7 hg with only 15 sample values, x= 31.9 hg, and s = 3.6 hg? What is the confidence interval for the population mean u? |hg < u< hg (Round to one decimal place as needed.)
4. At private college the achievement test is used for advanced study placement. Counselors selected a random sample of 144 students from the college and scored their tests by hand before sending them in for computer processing. For this sample, the mean was 450 and s = 29. Construct a 98% confidence interval for the mean.
Suppose the English department of a local university has a total of 105 faculty members. Of this number, 24 (about 23%) are part-time instructors. Is it appropriate to find a confidence interval for the percentage of part-time instructors in the department? Find a 95% confidence interval or explain why you should not find a confidence interval for the percentage of part-time instructors in the English department.
Imagine that you obtain a random sample of 125 M&M candies, and you notice that 28% of these candies are blue. If we convert the sample percentage of 0.28 to a sample proportion (by dividing 28 by 100), we get 0.28.
A learn-to-type software program claims that it can improve your typing skills. To test the claim and possibly help yourself out, you and six of your friends decide to try the program and see what happens. Use the table below to construct an 80% confidence interval for the true mean change in the typing speeds for people who have completed the typing program. Let Population 1 be the typing speed before taking the program and Population 2 be the typing speed after taking the program. Round the endpoints of the interval to one decimal place, if necessary. Typing Speeds (in Words per Minute) Before After 32 33 51 42 55 40 35 32 54 33 45 30 50 52
If n=430 and (p-hat) = 0.67, construct a 90% confidence interval. Give your answers to three decimals
Listed below are student evaluation ratings of courses, where a rating of 5 is for "excellent." The ratings were obtained at one university in a state. Construct a confidence interval using a 90% confidence level. What does the confidence interval tell about the population of all college students in the state? 4.0, 3.1, 4.0, 4.8, 3.1, 3.9, 3.6, 4.9, 4.2, 4.1, 4.4, 3.6, 3.2, 4.1, 3.7 O What is the confidence interval for the population mean p? <µ< (Round to two decimal places as needed.)
In a study of speed dating, male subjects were asked to rate the attractiveness of their female dates, and a sample of the results is listed below (1=not attractive; 10=extremely attractive). Construct a confidence interval using a 90% confidence level. What do the results tell about the mean attractiveness ratings of the population of all adult females? 5,7,2,9,4,4,6,9,7,8,6,8
The following is the number of hours of sleep obtained by eight college freshmen. Use the data to find a 92% confidence interval for the true mean number of hours of sleep by college freshmen. 7.5 8.0 6.5 24 8.5 6.5 7.0 7.5
I chose Option 1 for this week’s discussion post. I want to estimate the population mean number of times adults between the ages of 30 and 45 went to the grocery store in the last week. I spoke with 12 adults and asked them how many times they went to the grocery store in the last week. The results were 0, 2, 2, 7, 5, 1, 0, 3, 1, 1, 4, and 3. Now calculate a 95% confidence interval for the population mean. (Round to three decimal places)

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Here are summary statistics for randomly selected weights of newbon girls: n= 168, x 28.2 hg, s=7.3 hg. Construct a confidence interval estimate of the mean. Use a 95% confidence level. Are these results very different from the confidence interval 26.4 hg