Here are some equations that contain a variable and a list of values. Think about what each equation means and find a solution in the list of values. If you get stuck, draw a diagram. Be prepared to explain why your solution is correct. On the next screen you will match them with the answers. 1000 – a = 400 %3D 12.6 = b+ 4.1 8c = 8 10e = 1 h+ = 1 7.

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ISBN:9780470458365
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2.3 Using Structure to Find Solutions
Here are some equations that contain a variable and a
list of values. Think about what each equation means
and find a solution in the list of values. If you get stuck,
draw a diagram. Be prepared to explain why your
solution is correct. On the next screen you will match
them with the answers.
1000 – a = 400
|
12.6 = b + 4.1
8c = 8
10e = 1
h+
M
3/7
Transcribed Image Text:2.3 Using Structure to Find Solutions Here are some equations that contain a variable and a list of values. Think about what each equation means and find a solution in the list of values. If you get stuck, draw a diagram. Be prepared to explain why your solution is correct. On the next screen you will match them with the answers. 1000 – a = 400 | 12.6 = b + 4.1 8c = 8 10e = 1 h+ M 3/7
Expert Solution
Step 1: Equation 1

The equation 1000-a=400 means that when is subtracted from the number 1000, then the result is 400 or 400 is left.

Solve the equation by first subtracting 400 on both sides and then adding a on both sides of the equation to determine the value of a.

1000-a=4001000-a-400=400-4001000-400-a=0600-a=0600-a+a=0+a600=a

Therefore a=600.

Now substitute the value of a in the equation to check whether the solution is correct or not.

1000-a=4001000-600=400400=400

As the equation 400=400 is true, thus the solution is correct.

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