Hence, or otherwise, show that the solution of d²y dx² dy dx is 2 sinh t y = 2 sin sin ( substitution - 2 cosh x +ysinh*r=0, g(1) = 0, g(2) = 2, (cosh x cosh 1) (cosh 2 - cosh 1)) - this is a solution by direct

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Consider the functional
S[2] = [
is
dc [ u sinh x
2 sinh x
y =
Hence, or otherwise, show that the solution of
dy
d²y
dx²
dx
2 sin
مردم
sin
substitution
2y/²
sinh x
- 2 cosh x
(cosh x
(cosh 2
√2
"
cosh 1)
y(a) = A, y(b) = B, 0 < a < b.
+ysinh®æ=0, g(1)=0, y(2) = 2,
cosh 1)
this is a solution by direct
Transcribed Image Text:Consider the functional S[2] = [ is dc [ u sinh x 2 sinh x y = Hence, or otherwise, show that the solution of dy d²y dx² dx 2 sin مردم sin substitution 2y/² sinh x - 2 cosh x (cosh x (cosh 2 √2 " cosh 1) y(a) = A, y(b) = B, 0 < a < b. +ysinh®æ=0, g(1)=0, y(2) = 2, cosh 1) this is a solution by direct
Ş[y] = { L (xi y₁, y¹) dx : ;; 2= yt sin x
het
Euler- Lagrange Equation =
24- & (3)
Zysin x = 0
• coshx
ay'
u.=
= 0
2
y 'exs = di d
24 = 2y sinx
ay
then du = sinhx dx
year = A₁ y cb₁ = B₁ocacb.
you yếu sinh x
S[y] = (a (y² = 24/² =) sinhx dx
sinh
•Sinhb
Sinha (y² = 2 (y kus szrch x)²) daxi
si
sinh
Isinha:
Hence, the new.
•Sinhb
- Socha (y^² - 12/18 (19) ²); where un = simha
sinh
· U₂ =
sinh bị
independent variable is
•coshx.
Transcribed Image Text:Ş[y] = { L (xi y₁, y¹) dx : ;; 2= yt sin x het Euler- Lagrange Equation = 24- & (3) Zysin x = 0 • coshx ay' u.= = 0 2 y 'exs = di d 24 = 2y sinx ay then du = sinhx dx year = A₁ y cb₁ = B₁ocacb. you yếu sinh x S[y] = (a (y² = 24/² =) sinhx dx sinh •Sinhb Sinha (y² = 2 (y kus szrch x)²) daxi si sinh Isinha: Hence, the new. •Sinhb - Socha (y^² - 12/18 (19) ²); where un = simha sinh · U₂ = sinh bị independent variable is •coshx.
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