Help your customer to calculate the heat losses through a composite wall that includes an 8-mm-thick hardwood siding, 40-mm by 130-mm hardwood studs with glass fiber insulation (paper faced, 28 kg/m3 ), and a 12-mm layer of gypsum (vermiculite) wall board as shown. The wall is 2.5 m high by 6.5 m wide. - 20 °C Wood siding Stud 130 mm Insulation Wall board 21 °C 40 mm Figure 1: The top view of thecomposite wall.

Help your customer to calculate the heat losses through a composite wall that includes an 8-mm-thick hardwood siding, 40-mm by 130-mm hardwood studs with glass fiber insulation (paper faced, 28 kg/m3 ), and a 12-mm layer of gypsum (vermiculite) wall board as shown. The wall is 2.5 m high by 6.5 m wide. - 20 °C Wood siding Stud 130 mm Insulation Wall board 21 °C 40 mm Figure 1: The top view of thecomposite wall.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Concept explainers

Temperature Difference and Heat Transfer

Whenever there is a flow of heat flux resulting from a temperature gradient within the material or between two materials, there is heat transfer. Heat transfer primarily arises due to temperature differences between two bodies or within bodies. The term temperature gradient denotes temperature differences or variation of temperature due to change in some quantity. The fundamental use of the concept of temperature is found in the zeroth law of thermodynamics.

Question

Help your customer to calculate the heat losses through a composite wall that includes
an 8-mm-thick hardwood siding, 40-mm by 130-mm hardwood studs with glass fiber
insulation (paper faced, 28 kg/m3 ), and a 12-mm layer of gypsum (vermiculite) wall
board as shown. The wall is 2.5 m high by 6.5 m wide.
- 20 °C
Wood siding
Stud
130 mm
Insulation
Wall board
21 °C
40 mm
Figure 1: The top view of thecomposite wall.

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