Help with Time/space complexity. Would the time complexity be O(n^2) or O(n*m) ?
Help with Time/space complexity. Would the time complexity be O(n^2) or O(n*m) ?
Database System Concepts
7th Edition
ISBN:9780078022159
Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Chapter1: Introduction
Section: Chapter Questions
Problem 1PE
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Help with Time/space complexity. Would the time complexity be O(n^2) or O(n*m) ?
![def longestCommonPrefix(self, strs: List[str]) -> str:
def lcp(strs):
if strs ==
2
4 v
:
5
return
if len(strs)
return strs[0]
6 v
== 1:
7
8.
strs[0]
prefix =
prefixlength
9.
10
len(prefix)
%3D
11
12 v
for word in strs[1:]:
while prefix != word[0:prefixLength]: # flower != flow
prefix = prefix[0:(prefixLength-1)] #flowe
prefixlength
13 v
14
%3D
15
-= 1
16
17 v
if prefixLength
== 0:
18
return
19
return prefix
20](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F5944382a-def4-4d12-af6b-dbe75c2d36fe%2Fdfe2a24c-212a-4fa3-ae4a-0b4d97744353%2Fpylncp9_processed.jpeg&w=3840&q=75)
Transcribed Image Text:def longestCommonPrefix(self, strs: List[str]) -> str:
def lcp(strs):
if strs ==
2
4 v
:
5
return
if len(strs)
return strs[0]
6 v
== 1:
7
8.
strs[0]
prefix =
prefixlength
9.
10
len(prefix)
%3D
11
12 v
for word in strs[1:]:
while prefix != word[0:prefixLength]: # flower != flow
prefix = prefix[0:(prefixLength-1)] #flowe
prefixlength
13 v
14
%3D
15
-= 1
16
17 v
if prefixLength
== 0:
18
return
19
return prefix
20
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