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Help with Ochem... I need to write the stoichiometric equations for the following redox ... the reduction of benzophenone by borohydride First show the 2 half redox stoichiometric equations from the reaction and then combine the 2 half reactions to show the final balance redox equation stoichiometrically.  ***I do not need the structural mechanism...only the stoichiometric equations*** Additional info: use the following amounts 0.0025 mol C13H10O 0.100 g BH4 I've started with the unbalance equation: C13H10O  +  BH4  ------>  C13H12O  +  BO3 -3 I also have this C13H10O   ----> C13H12O                   (Reduction) BH4  ----->  BO3                                  (Oxidation)

Help with Ochem... I need to write the stoichiometric equations for the following redox ... the reduction of benzophenone by borohydride First show the 2 half redox stoichiometric equations from the reaction and then combine the 2 half reactions to show the final balance redox equation stoichiometrically.  ***I do not need the structural mechanism...only the stoichiometric equations*** Additional info: use the following amounts 0.0025 mol C13H10O 0.100 g BH4 I've started with the unbalance equation: C13H10O  +  BH4  ------>  C13H12O  +  BO3 -3 I also have this C13H10O   ----> C13H12O                   (Reduction) BH4  ----->  BO3                                  (Oxidation)

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Help with Ochem...

I need to write the stoichiometric equations for the following redox ... the reduction of benzophenone by borohydride

First show the 2 half redox stoichiometric equations from the reaction and then combine the 2 half reactions to show the final balance redox equation stoichiometrically. 

***I do not need the structural mechanism...only the stoichiometric equations***

Additional info: use the following amounts

0.0025 mol C13H10O

0.100 g BH4

I've started with the unbalance equation:

C13H10O  +  BH4  ------>  C13H12O  +  BO3 -3

I also have this

C13H10O   ----> C13H12O                   (Reduction)

BH4  ----->  BO3                                  (Oxidation)

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