Hello I need help with these question: based on the example I included, what other trials and different concentrations could I have used to end up with the same overall reaction order of 2, and what would be the rate law formula. ## Determination of Reaction Order### Part (a)The equation given is:\[\frac{262}{131} = \frac{k[0.10M]^a [0.10M]^x}{k[0.20M]^a [0.10M]^x}\]Simplifying the equation:\[\frac{2}{1} = \frac{0.5^a}{0.5^x} = 4\]From this, we can determine that:\[\left(\frac{1}{262}\right) \div \left(\frac{1}{131}\right) = 0.5^a\]Simplifying further:\[\frac{0.5}{0.5} = 0.5^a\]Hence:\[1 = a\]### Part (b)The equation here is:\[\frac{262}{131} = \frac{k[0.10M]^a [0.10M]^b}{k[0.10M]^a [0.20M]^b}\]Simplifying the equation:\[\frac{2}{1} = \frac{0.5^b}{0.5^b} = 4\]Thus:\[\left(\frac{1}{262}\right) \div \left(\frac{1}{131}\right) = 0.5^b\]Simplifying further:\[\frac{0.5}{0.5} = 0.5^b\]Hence:\[1 = b\]### ConclusionThe overall order of the reaction is:\[\text{Overall order} = 2\]This analysis determines the individual reaction orders with respect to each reactant, concluding with an overall reaction order of 2. **Prelaboratory Exercise**1. **Given the following data, determine the orders with respect to the concentrations of substances A and B in the reaction:** \[ A + B \rightarrow \text{products} \] | [A]initial | [B]initial | Time for reaction | |------------|------------|-------------------| | 0.10 M | 0.10 M | 262 s | | 0.20 M | 0.10 M | 131 s | | 0.30 M | 0.10 M | 87 s | | 0.20 M | 0.20 M | 66 s | | 0.10 M | 0.20 M | 131 s | *Instructions*: Use the above data to calculate the reaction orders with respect to substances A and B. Analyze how the change in concentration affects the reaction time.2. **What must be the units of the specific rate constant in Prelaboratory Question 1, given that the rate of reaction would be measured in M/s?** *Hint*: Consider the general rate law and the units involved in the calculations to determine the units of the rate constant.

The objective of the question is to determine the rate law of the reaction.The given chemical equation is depicted as follows-From the experimental data,The orders for A and B come out to be for both the reactants.The rate law relates the concentration of reacting species and the rate constant.The rate law is expressed as follows-or it can be written as follows-The rate constant can be predicted as follows-From the first trial,So, the rate law is expressed as follows-The rate law of the reaction is expressed as follows-