Hello I am being asked to find the probability that a policy costs more than $1750 to have my answer right.

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Hello I am being asked to find the probability that a policy costs more than $1750 to have my answer right. 

 

A study by Quadrant Information Services commissioned by Insure.com  calculated auto insurance rates for each of the 50 states; and as a result, the average annual rate for the United States was $1,317. Suppose annual rates of auto insurance in the United States are normally distributed with a standard  deviation of $324.

According to MoneyGeek, a state minimum auto insurance policy in Florida costs an average of $1123 pe

 

Answwe: What is the probability that a randomly selected auto insurance rate in the United States would be greater than $1,750?

Value standardization is required using the following formula below in order to determine the likelihood that a car insurance rate chosen at random in the United States would be higher than $1,750:

z = (x - mu) / sigma

mu is the mean of the distribution, x is the interest value, and sigma is the standard deviation. Substituting the given values,

z = (1750 - 1317) / 324 = 1.34

We can calculate the probability of selecting an auto insurance rate above $1,750 by finding the probability of z being greater than 1.34 using a standard normal table or calculator. The result is approximately 9.01%, which means that there is a 9.01% chance of selecting an auto insurance rate above $1,750 from a random sample in the United States. This result is not unexpected, considering that $1,750 is higher than the mean and one standard deviation, suggesting that it is a relatively high value.

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