Heat the claim about the difference between two population means p, and ₂ at the level of significance a Assume the samples are random and independent, and the populations are normally distributed Clam pa=0.01 Population parameters, 33, ₂15 Sample statistics x,-18, n, 27, X=20, n₂ = 26 Determine the alternative hypothesis Determine the standardized test statstic z=(Round to two decimal places as needed) Determine the P-value. P-value- (Round to three decimal places as needed) What is the proper decision? OA Fal to reject H, There is not enough evidence at the 1% level of significance to reject the claim OB Reject H, There is not enough evidence at the 1% level of significance to reject the claim OC. Fal to reject H, There is enough evidence at the 1% level of significance to reject the claim OD. Rejed H, There is enough evidence at the 1% level of significance to reject the clam

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### Testing the Difference Between Two Population Means

**Objective:** Test the claim about the difference between two population means \( \mu_1 \) and \( \mu_2 \) at the level of significance \( \alpha \). Assume the samples are random and independent, and the populations are normally distributed.

#### Given Data:
- **Claim:** \( H_1: \mu_1 \ne \mu_2 \)
- **Significance Level:** \( \alpha = 0.01 \)
- **Population Parameters:** 
  - Standard Deviation of Population 1 (\( \sigma_1 \)) = 3.3
  - Standard Deviation of Population 2 (\( \sigma_2 \)) = 1.5
- **Sample Statistics:**
  - Sample Mean of Group 1 (\( \bar{x}_1 \)) = 11
  - Sample Size of Group 1 (\( n_1 \)) = 27
  - Sample Mean of Group 2 (\( \bar{x}_2 \)) = 20
  - Sample Size of Group 2 (\( n_2 \)) = 26

### Steps for Hypothesis Testing

1. **Determine the Alternative Hypothesis:**
   \[
   H_1: \mu_1 \ne \mu_2
   \]

2. **Determine the Standardized Test Statistic:**
   Use the formula for the Z-test statistic for difference between two means:
   \[
   z = \frac{(\bar{x}_1 - \bar{x}_2)}{\sqrt{\left(\frac{\sigma_1^2}{n_1}\right) + \left(\frac{\sigma_2^2}{n_2}\right)}}
   \]
   Substituting the given values:
   \[
   z = \frac{(11 - 20)}{\sqrt{\left(\frac{3.3^2}{27}\right) + \left(\frac{1.5^2}{26}\right)}} 
   \]
   Perform the calculations:
   \[
   z = \frac{-9}{\sqrt{\left(\frac{10.89}{27}\right) + \left(\frac{2.25}{26}\right)}} \approx \frac{-9}{\sqrt{0.4033 + 0.0865}} \approx \frac{-9
Transcribed Image Text:### Testing the Difference Between Two Population Means **Objective:** Test the claim about the difference between two population means \( \mu_1 \) and \( \mu_2 \) at the level of significance \( \alpha \). Assume the samples are random and independent, and the populations are normally distributed. #### Given Data: - **Claim:** \( H_1: \mu_1 \ne \mu_2 \) - **Significance Level:** \( \alpha = 0.01 \) - **Population Parameters:** - Standard Deviation of Population 1 (\( \sigma_1 \)) = 3.3 - Standard Deviation of Population 2 (\( \sigma_2 \)) = 1.5 - **Sample Statistics:** - Sample Mean of Group 1 (\( \bar{x}_1 \)) = 11 - Sample Size of Group 1 (\( n_1 \)) = 27 - Sample Mean of Group 2 (\( \bar{x}_2 \)) = 20 - Sample Size of Group 2 (\( n_2 \)) = 26 ### Steps for Hypothesis Testing 1. **Determine the Alternative Hypothesis:** \[ H_1: \mu_1 \ne \mu_2 \] 2. **Determine the Standardized Test Statistic:** Use the formula for the Z-test statistic for difference between two means: \[ z = \frac{(\bar{x}_1 - \bar{x}_2)}{\sqrt{\left(\frac{\sigma_1^2}{n_1}\right) + \left(\frac{\sigma_2^2}{n_2}\right)}} \] Substituting the given values: \[ z = \frac{(11 - 20)}{\sqrt{\left(\frac{3.3^2}{27}\right) + \left(\frac{1.5^2}{26}\right)}} \] Perform the calculations: \[ z = \frac{-9}{\sqrt{\left(\frac{10.89}{27}\right) + \left(\frac{2.25}{26}\right)}} \approx \frac{-9}{\sqrt{0.4033 + 0.0865}} \approx \frac{-9
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