please solve the problem in the picture Head Loss CalculationWhat is the head loss along a 1000 m straight pipe (inside diameter: 0.2 m) that delivers water (kinematicviscosity: 1 x 10-6 m²/s) at 0.032 m³/s? Absolute roughness of pipe = 0.1 mm.ff64Re0.255.74 2[log10(3.7D+ Re0.9)]

Given data:Length of pipe, L=1000mDiameter of pipe, D=0.2mKinematic viscosity, υ=1×10−6m2/sflow rate…

Answered: Head Loss Calculation What is the head…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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For all pipes, the roughness coefficient n = 0.011. Find in cms:a.)Discharge at pipe 1/reservoir A.b.)Discharge at pipe 2/reservoir B.c.)Discharge at pipe 3/reservoir C. PIPELINE LENGTH (m) DIAMETER (mm) 1 1241 344 2 912 211 3 1524 122
a.) Q=0.56m/s. V=1.16m/s b.)D=420mm. q=5.5x10^-3m^3/s That is the answer need some solutions
The data in the table below is for a closed-polygon traverse. Course Azimuth Length (m) AB 75°14'47" 519.674 BC 455.265 CD DE EA Interior Angles A = 12°25'31" B 48°19'25" 433.426 C = 126°37'24" 425.558 D = 46°03'36" 109.434 E = 306° 34'19" Part A Compute the preliminary azimuths. O AZAB = 57°14'47". Azpc = 303°34′09", AzcD=250°11'30". AZDE=116°15'03". AZEA = 242° 49'19" O AZAB = 75°00'47", AZ BC = 303°00'09", AzcD = 250°00'30", AZDE = 116°00'03", AZEA = 242°00'19" O AZAB = 75°14'47". AzBc = 313° 34'09", AzcD = 25°11'30", AZDE = 116°10'00", AZEA = 224° 49'19" O AZAB = 75°14'47". AzBC = 303°34'09", AzcD = 250°11'30". AZDE = 116°15'03". AZEA = 242° 49'19" Part B Compute the unadjusted departures. Express your answers in meters to six significant figures and separated by commas. AB, BC, CD, DE, EA= Part C vec IVE ΑΣΦΠ ← A Compute the unadjusted latitudes. Express your answers in meters to six significant figures and separated by commas. AB, BC, CD, DE, EA= ΠΑΠΑΣΦ Π vec ^ A ? ? m, m, in mi,…
The flanged steel cantilever beam with riveted bracket is subjected to the couple and two forces shown, and their effect on the design of the attachment at A must be determined. Replace the two forces and couple by an equivalent couple M and resultant R at A. The couple is positive if counterclockwise, negative if clockwise. 1.90 KN 0.69 m 2.27 m- 66° A 1 L--x 490 N·m 1.34 KN 0.13 m 0.13 m
Given: As = 3m2 C = 0.92 Ao = 0.01m2 Find: Determine the time for the depth of liquid in the tank to be 0.8m
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Q (5-7)/ Water flows uniformly in an earth rectangular cross section open. channel. Data available are: wasa.t €18.8 Longitudinal slope of bed level of the channel S, = 0.0004, n = wal aid sell 0.01 {s/m(13)), water flow rate Q=800 (m³/s) and B= 200 (m)..d =X Calculate values of the followings: 858 ETB)(-10) - CI8.8) - Water flow depth y and water flow velocity v in the channel.
Q3 Consider a flow field represented by the stream function ψ = 24 x3y - 26 x2y2 + 24 xy3. Is this a possible two-dimensional incompressible flow? Is the flow irrotational? Discuss the reasons against your findings.
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O. No. 3 A right angled triangular notch was to measure a discharge of 0.28 m3/s from a rectangular reservoir. It was found to have an error (dHị to be R mm in ncasuring hcad of notch. Determine the percenlage error in discharge as dQ/Q. Take Cd - 0.6 R=100 solve with R=100
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1. THERE IS A LEAK IN A HORIZONTAL 300 MMDIAMETER PIPELINE. UPSTREAM FROM THE LEAK TWOGAGES 600 METER APART SHOWED A DIFFERENCE OF140 ???. DOWNSTREAM FROM THE LEAK TWO GAGES600 METER APART SHOWED A DIFFERENCE OF 126??? . ASSUMING ? = 0.025. HOW MUCH WATER ISBEING LOST FROM THE PIPE. show answer in litre per sec

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Head Loss Calculation What is the head loss along a 1000 m straight pipe (inside diameter: 0.2 m) that delivers water (kinematic viscosity: 1 x 10-6 m²/s) at 0.032 m³/s? Absolute roughness of pipe = 0.1 mm. f f 64 Re 0.25 5.74 2 [log10(3.7D+ Re0.9 )]