he standard deviation and the mean of 25 students scores are 10 and 38, respectively. Construct a 99% confidence interval.
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- You are interested in seeing whether emotions impact decision making. You have three groups--a happy group, a sad group, and a neutral group. For the happy group there are 5 participants and the mean risky decision making score 5.0 with a standard deviation of 0.7. For the sad group there are 5 participants and the mean risky decision making score 5.4 with a standard deviation of 1.1. For the neutral group there are 5 participants and the mean risky decision making score 5.8 with a standard deviation of 2.8. The sum of squares between samples is equal to 1.6. The sum of squares within samples is equal to 38.0. What is the mean square between samples?In a normally distributed data set of how long customers stay in your store, the mean is 43.5 minutes and the standard deviation is 3.9 minutes. Within what range would you expect 95% of your customers to stay in your store?Use z scores to compare the given values. The tallest living man at one time had a height of 225 cm. The shortest living man at that time had a height of 136.8 cm. Heights of men at that time had a mean of 173.31 cm and a standard deviation of 5.54 cm. Which of these two men had the height that was more extreme?
- A nutritionist conducted a study on the eating patterns of early adolescent boys and girls. Calorie intake is normally distributed for both boys and girls. The population means are 3300 calories per day for boys and 2900 calories per day for girls. The population standard deviations are 790 for boys and 720 for girls. The nutritionist believes that children may have an eating disorder if they are in the bottom 2% the distribution. Based on this, if a child’s intake is1600 calories per day, should the nutritionist be concerned that this child may have an eating disorder? (Compute for each gender separately). Does it make a difference if this child is a boy or a girl? Explain your answer. What proportion of girls consume between 2000 and 2400 calories per day? Is the proportion of boys who consume between 2000 and 2400 calories per day the same, higher, or lower than the proportion of girls who consume between 2000 and 2400 calories per day? Explain your answer.A professor using an open-source introductory statistics book predicts that 60% of the students will purchase a hard copy of the book, 25% will print it out from the web, and 15% will read it online. She has 200 students this semester. Assuming that the professor's predictions were correct, calculate the expected number of students who read the book online.The mean composite score for seniors who took the SAT in 2010 was 1068. If the standard deviation for the same year was 100, what would the z score be for a person who scored in the 98th percentile? a. +2.00 b. -1.00 c. +1.00 d. -2.00
- Fandango is experiencing record high sales and rentals for films over the course of the pandemic. They are trying to compete on the VOD scene by offering frequent sales on new “Home Theater" releases of films. On average, these films rent for around $19.99 per film with the premium films. There is a standard deviation for the rental prices of $2.50. Fandango wants to have lower prices but not low enough to be in the bottom 5% of rental prices. They utilize random samples of 10 services for a particular film to investigate. What should the lowest price be so that they are not in the bottom 5%?You are interested in seeing whether emotions impact decision making. You have three groups--a happy group, a sad group, and a neutral group. For the happy group there are 5 participants and the mean risky decision making score 5.0 with a standard deviation of 0.7. For the sad group there are 5 participants and the mean risky decision making score 5.4 with a standard deviation of 1.1. For the neutral group there are 5 participants and the mean risky decision making score 5.8 with a standard deviation of 2.8. The sum of squares between samples is equal to 1.6. The sum of squares within samples is equal to 38.0. What is the degrees of freedom within samples?The Jimmy John’s store manager on Hwy. 46 wanted to know more about their customers. She decides to focus on two variables: the average ticket spent by customers, and whether customers would consider purchasing ice cream if it was available. She interviewed 54 customers over a two-week period. Results of her research showed average ticket was $10.89 with a standard deviation of $2.35. Twenty-two customers said they would purchase ice cream if it was available. INCLUDE EXCEL EQUATIONS. Assume the store manager wants to conduct a similar survey at the National Road store. Answer the following questions: c. What sample size is needed to have 95% confidence of estimating the population average ticket in this store to within plus/minus $1.00 if the standard deviation is assumed to be $2.35? d. How many customers need to be selected to have 90% confidence of estimating the population proportion who would consider purchasing ice cream plus/minus 0.10 (10%)?
- You are interested in seeing whether emotions impact decision making. You have three groups--a happy group, a sad group, and a neutral group. For the happy group there are 5 participants and the mean risky decision making score 5.0 with a standard deviation of 0.7. For the sad group there are 5 participants and the mean risky decision making score 5.4 with a standard deviation of 1.1. For the neutral group there are 5 participants and the mean risky decision making score 5.8 with a standard deviation of 2.8. The sum of squares between samples is equal to 1.6. The sum of squares within samples is equal to 38.0. What is the mean square between samples?A distribution of scores has no mode and the same median and mean values. This indicates that theUse the range rule of thumb to identify the values that are significantly low, the values that are signficantly high, and the values that are neither significantly low nor significantly high. A test is used to assess readiness for college. In a recent year, the mean test score was 20.5 and the standard deviation was 5.1. Identify the test scores that are significantly low or significantly high
