he simply supported beam shown, calculate the internal reactions at point C. 9 kip/ft A B |C 6 ft 18 ft

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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For the simply supported beam shown, calculate the internal reactions at point C.
19 kip/ft
A
В
|C
6 ft
-18 ft
Transcribed Image Text:For the simply supported beam shown, calculate the internal reactions at point C. 19 kip/ft A В |C 6 ft -18 ft
1
3
4
5. Internal Loadings
Sign Convention
N
Positive normal force
Positive shear
M
Positive moment
1
2
3
4
5. Internal Loadings
Sample Problem 5
Determine the internal normal force, shear force, and moment at
point C.
40 kN
8 kN/m
60°
В
А
3 m
3 m
3 m
0.3 m
1
3
4
5. Internal Loadings
40 kN
Sample Problem 5
8 kN/m
60°
Given:
В
A
Required: N., Ve, Mc
3 m
3 m
3 m
0.3 m
Solution:
40 kN
8 kN/m
Am,
60°
В
3 m
3 m
3 m
0.3 m
1
2
3
5. Internal Loadings
Resultant a ea
Location (entroid
4
Sample Problem 5
24KN
40 kN
12KN
8 kN/m
Am
Mc
Mc
60°
B.
A
3 m
3 m
3 m
Mc
0.3 m
- Ne - 40 (cosG0) -0
Nc= -20kN, T
N: 20 KN, C
Vc- 24 -12 -40sinGo=
-24 (15)-12 (4) - 40sinuolG3
- Me :0
Mc:-302-2384 kN m
Vc: 70.6410 KN
Transcribed Image Text:1 3 4 5. Internal Loadings Sign Convention N Positive normal force Positive shear M Positive moment 1 2 3 4 5. Internal Loadings Sample Problem 5 Determine the internal normal force, shear force, and moment at point C. 40 kN 8 kN/m 60° В А 3 m 3 m 3 m 0.3 m 1 3 4 5. Internal Loadings 40 kN Sample Problem 5 8 kN/m 60° Given: В A Required: N., Ve, Mc 3 m 3 m 3 m 0.3 m Solution: 40 kN 8 kN/m Am, 60° В 3 m 3 m 3 m 0.3 m 1 2 3 5. Internal Loadings Resultant a ea Location (entroid 4 Sample Problem 5 24KN 40 kN 12KN 8 kN/m Am Mc Mc 60° B. A 3 m 3 m 3 m Mc 0.3 m - Ne - 40 (cosG0) -0 Nc= -20kN, T N: 20 KN, C Vc- 24 -12 -40sinGo= -24 (15)-12 (4) - 40sinuolG3 - Me :0 Mc:-302-2384 kN m Vc: 70.6410 KN
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