The Ka of Benzoic acid (C6H5COOH) is 6.3 x 10-5. A 0.72 M C6H5COOH of 40.0 mL is titrated with 0.48 M NaOH. Which of the following is correct for the following two processes? CHOOSE ONE OPTION ONLY(1) After add _______ ml of NaOH into the above 0.72 M C6H5COOH of 40.0 mL, we have [ C6H5COOH ] = [ C6H5COO- ] in the resulting solution.(2) After add _______ ml of NaOH into the above 0.72 M C6H5COOH of 40.0 mL, we have [ C6H5COOH ] = [OH- ] in the resulting solution.Options (Choose one):a. The answer for (1) is 40.0 ml. The answer for (2) is 20.0 ml.b. The answer for (1) is 20.0 ml. The answer for (2) is 40.0 ml.c. The answer for (1) is 30.0 ml. The answer for (2) is 60.0 ml.d. The answer for (1) is 60.0 ml. The answer for (2) is 30.0 ml.e. None of the above is correct.

Answer - The correct option is (c) The answer for (1) is 30.0 ml. The answer for (2) is 60.0 ml. Solution -

Answered: he Ka of Benzoic acid (C6H5COOH) is 6.3…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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The K_a of Benzoic acid (C₆H₅COOH) is 6.3 x 10^-5. A 0.72 M C₆H₅COOH of 40.0 mL is titrated with 0.48 M NaOH. Which of the following is correct for the following two processes? CHOOSE ONE OPTION ONLY

(1) After add _______ ml of NaOH into the above 0.72 M C₆H₅COOH of 40.0 mL, we have [ C₆H₅COOH ] = [ C₆H₅COO^-] in the resulting solution.

(2) After add _______ ml of NaOH into the above 0.72 M C₆H₅COOH of 40.0 mL, we have [ C₆H₅COOH ] = [OH^-] in the resulting solution.

Options (Choose one):

a. The answer for (1) is 40.0 ml. The answer for (2) is 20.0 ml.

b. The answer for (1) is 20.0 ml. The answer for (2) is 40.0 ml.

c. The answer for (1) is 30.0 ml. The answer for (2) is 60.0 ml.

d. The answer for (1) is 60.0 ml. The answer for (2) is 30.0 ml.

e. None of the above is correct.

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