he head librarian at the Library of Congress has asked her assistant for an interval estimate of the mean number of books checked out each day. The assistant provides the following interval estimate: from 740 to 920 books per day. If the head librarian knows that the population standard deviation is 150 books checked out per day, and she asked her assistant for a 95% confidence interval, approximately how large a sample did her assistant use to determine the interval estimate?     4     125     11     13

Q: e: For each confidence interval, enter your answer in the form (LCL, UCL). You must include the…

A: Sample size n =47 Sample mean=109 Population standard deviation =32

Q: Find the sample size need to find the Population Mean if the margin of error is $105, the confidence…

A: Solution: From the given information, confidence level is 0.95, σ=315 and E=105.

Q: Use the given confidence interval to find the margin of error and the sample mean. .734, .760

A: From the given information, the confidence interval is (0.734, 0.760). It can be expressed in,

Q: Calculate the lower 95% confidence interval for the population mean. (round to the nearest tenth)…

A: given data n = 31σ2 = 15∴σ = 15 = 3.873x¯ = 5695% ci for μ = ?

Q: A Seattle consumer agency believes that plumbers’ rates are too high and wants to estimate the mean…

A: GivenConfidence Interval(c)=95%Margin of Error(E)=3%=0.03Let…

Q: In a Statistics examination, the mean score is 82 and the standard deviation is 3.5. If the teacher…

A:

Q: The head librarian at the Library of Congress has asked her assistant for an interval estimate of…

A: We have given that  95% C.I = ( 740 , 920 ) Standard deviation =150

Q: Construct a confidence interval for the mean of the paired differences for the two populations with…

A: Given, sample size (n) = 37 sample mean ( d̄ ) = 4.132  Standard deviation ( Sd )  = 0.749…

Q: Determine the sample size for the estimate of u if the margin of error E= 0.10, o=0.85, and the…

A: Given,Margin of error, E = 0.10Population standard deviation, σ = 0.85Confidence level, C = 99% =…

Q: You must estimate the mean temperature (in degrees Fahrenheit) with the following sample…

A: Obtain the 99% confidence interval for the population mean temperature. The 99% confidence interval…

Q: Suppose you calculate a 99% confidence interval to be: 13.05 to 20.75. Determine the margin of error

A: Given data: The given upper limit is b=20.75. The given lower limit is a=13.05.   The expression for…

Q: the population standard deviation have to be in order for the standard error to be 1? 2 ? 5 ? 100

A: It is given that  Sample size, n = 36

Q: A statistics practitioner took a random sample of 56 observations from a population whose standard…

A: We have given that,  Sample size (n) = 56, population standard deviation (σ) = 35 and sample mean…

Q: Of the following general derivations, choose the formula that you need for computing a confidence…

A: Confidence interval = ??

Q: Among various ethnic groups, the standard deviation of heights is known to be approximately three…

A: We wish to construct a confidence interval for the mean height of male Swedes.The random variable…

Q: READ AND SOLVE THE FOLLOWING: Interval Estimate of Population Mean 1. Suppose that the amount of…

A: We. Have to find confidence interval for given data..

Q: The University of Sydney conducted a survey to find out the average number of hours an academic…

A:

Q: A statistics practitioner took a random sample of 43 Note: For each confidence interval, enter your…

A: n = 43 standard deviation = 27 mean = 104 95% confidence interval for mean is given by  x±zα2*σn 104…

Q: atistics practitioner took a random sample of 49 observations from a population whose standard…

A: Sample size n =49 Sample mean=103 Population standard deviation =25

Q: In a survey of 2009 adults in a recent year, 1263 say they have made a New Year's resolution.…

A:

Q: FIND t a n = 15 for the 98% confidence interval for the mean.

A: Provided information that, n=15 Alpha (α)=1-0.98=0.02 α/2=0.01

Q: A new fertilizer was applied to the soil of 222 bean plants. 28% showed increased growth. Find the…

A:

Q: The principal randomly selected six students to take an aptitude test. Their scores were 79 88 83 80…

A: " Since you have posted a question with multiple sub-parts, we will solve the first three subparts…

Q: The percent fo Coloradans that own a Subaru is 56%. If you were to take a random sample of size 70,…

A: We have given that,  Let X be the random variable from binomial distribution with probability (p) =…

Q: A new fertilizer was applied to the soil of 218 bean plants. 27% showed increased growth. Find the…

A: Given Information: Sample size (n) = 218 Proportion p^= 27% = 0.27 To find the margin of error and…

Q: Your state is considering raising the legal age for consumption of alcoholic beverages to 21 years…

A: p = 0.5 Margin of error = 0.01

Q: The annual earnings​ (in dollars) of 35 randomly selected microbiologists are shown in the data…

A: The objective of this question is to calculate the sample mean, sample standard deviation, and…

Q: A confidence interval was constructed to approximate a population proportion. The interval was from…

A: Given Data Lower limit,LL = 12.5 upper limit,UL = 18.5

Q: The annual earnings​ (in dollars) of 35 randomly selected microbiologists are shown in the data…

A: Given information: The annual earnings (in dollars) of n = 35 randomly selected microbiologists are…

Q: A grocer finds that the cantaloupes in his store have weights with mean 0.7 kg and standard…

A: Given, Mean weight of cantaloupes is 700 gm. Standard deviation is 53 gm

Q: A statistics practitioner took a random sample of 59 observations from a population whose standard…

A: sample size(n)=59 Population standard deviation(σ)=32 Mean(x)=95

Q: A statistics practitioner took a random sample of 49 observations from a population and computed the…

A: According to the given information in this question, we need to answer three subparts

Q: A statistics practitioner took a random sample of 43 observations from a population whose standard…

A: We have given that,  sample mean (x̄) = 109, standard deviation (σ) = 30 and sample size (n) = 43

Q: ou are given the smaple mean and the population m standard deviation. Use this info to construct the…

A:

Q: A poll of 2612 U.S. adults found that 15% regularly used Facebook as a news source. Find the margin…

A: The margin of error is defined as MOEγ=zγ×σn,γ is the confidence level,σ is the sample standard…

Q: How much money do winners go home with from the television quiz show Jeopardy? To determine an and…

A: