he freezing point of benzene, C6H6, is 5.500 °C at 1 atmosphere. Kbenzene) = -5.12 °C/m a laboratory experiment, students synthesized a new compound and found that when 11.50 grams of the compound were dissolved in 250.5 grams of benzene, the solution began to freeze at 4.685 °C. The compou o be nonvolatile and a non-electrolyte. /hat is the molecular weight they determined for this compound ? g/mol
he freezing point of benzene, C6H6, is 5.500 °C at 1 atmosphere. Kbenzene) = -5.12 °C/m a laboratory experiment, students synthesized a new compound and found that when 11.50 grams of the compound were dissolved in 250.5 grams of benzene, the solution began to freeze at 4.685 °C. The compou o be nonvolatile and a non-electrolyte. /hat is the molecular weight they determined for this compound ? g/mol
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Chapter1: Chemical Foundations
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![The freezing point of benzene, C6H6, is 5.500 °C at 1 atmosphere. Kf(benzene) = -5.12 °C/m
In a laboratory experiment, students synthesized a new compound and found that when 11.50 grams of the compound were dissolved in 250.5 grams of benzene, the solution began to freeze at 4.685 °C. The compound was also found
to be nonvolatile and a non-electrolyte.
What is the molecular weight they determined for this compound ?
g/mol](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F966b9752-0e6e-47d7-af8f-ce4bbf704a72%2Fc647b6df-ecce-4142-9f69-c79b9a6765ce%2F4o5hspq_processed.png&w=3840&q=75)
Transcribed Image Text:The freezing point of benzene, C6H6, is 5.500 °C at 1 atmosphere. Kf(benzene) = -5.12 °C/m
In a laboratory experiment, students synthesized a new compound and found that when 11.50 grams of the compound were dissolved in 250.5 grams of benzene, the solution began to freeze at 4.685 °C. The compound was also found
to be nonvolatile and a non-electrolyte.
What is the molecular weight they determined for this compound ?
g/mol
![Boiling Point Elevation/Freezing Point Depression
AT= m K
where, for freezing point depression:
AT= T(pure solvent) - T(solution)
and for boiling point elevation:
AT= T(solution) - T(pure solvent)
m = (# moles solute / Kg solvent)
Kp = boiling point elevation constant.
Kf = freezing point depression constant.
K, and Kf depend only on the SOLVENT. Below are some common values. Use these values for the calculations that follow.
Solvent
Formula
Kh(^C / m) KfºC/m)
Water
H20
0.512
1.86
Ethanol
CH3CH2OH
1.22
1.99
Chloroform CHC13
3.67
Benzene
CGH6
2.53
5.12
Diethyl ether CH3CH2OCH2CH3
2.02](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F966b9752-0e6e-47d7-af8f-ce4bbf704a72%2Fc647b6df-ecce-4142-9f69-c79b9a6765ce%2F2f5l404_processed.png&w=3840&q=75)
Transcribed Image Text:Boiling Point Elevation/Freezing Point Depression
AT= m K
where, for freezing point depression:
AT= T(pure solvent) - T(solution)
and for boiling point elevation:
AT= T(solution) - T(pure solvent)
m = (# moles solute / Kg solvent)
Kp = boiling point elevation constant.
Kf = freezing point depression constant.
K, and Kf depend only on the SOLVENT. Below are some common values. Use these values for the calculations that follow.
Solvent
Formula
Kh(^C / m) KfºC/m)
Water
H20
0.512
1.86
Ethanol
CH3CH2OH
1.22
1.99
Chloroform CHC13
3.67
Benzene
CGH6
2.53
5.12
Diethyl ether CH3CH2OCH2CH3
2.02
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