he force diagram below shows a box accelerating to the right on a horizontal surface of negligible friction. The tension T is exerted at an angle of 30˚ above the horizontal. If μ is the coefficient of kinetic friction between the box and the surface, which of the following is a correct mathematical equation derived by applying Newton’s second law to the box? aa = (Tcos(θ) - μMg)/M ba = (Tsin(θ) - μMg)/M ca = (Tcos(θ) - μ(Mg - Tsin(θ))/M da = (Tcos(θ) - μ(Mg + Tsin(θ))/M The image illustrates a free-body diagram of an object on a flat surface, showing the different forces acting upon it.- **N**: This represents the normal force, acting vertically upward, perpendicular to the surface.- **Mg**: This denotes the gravitational force (weight) acting downwards on the object, where *M* is the mass and *g* is the acceleration due to gravity.- **f**: This is the frictional force acting horizontally to the left, opposing the motion of the object.- **T**: This symbolizes the tension force acting on the object, directed diagonally upwards to the right.- **θ**: This represents the angle between the tension force **T** and the horizontal axis.The diagram helps in understanding how these forces interact and influence the motion and equilibrium of the object.

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Description: he force diagram below shows a box accelerating to the right on a horizontal surface of negligible friction. The tension T is exerted at an angle of 30˚ above the horizontal. If μ is the coefficient of kinetic friction between the box and the surfac

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College Physics

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ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

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he force diagram below shows a box accelerating to the right on a horizontal surface of negligible friction.

The tension T is exerted at an angle of 30˚ above the horizontal. If μ is the coefficient of kinetic friction between the box and the surface, which of the following is a correct mathematical equation derived by applying Newton’s second law to the box?

a	a = (Tcos(θ) - μMg)/M
b	a = (Tsin(θ) - μMg)/M
c	a = (Tcos(θ) - μ(Mg - Tsin(θ))/M
d	a = (Tcos(θ) - μ(Mg + Tsin(θ))/M

The image illustrates a free-body diagram of an object on a flat surface, showing the different forces acting upon it.

- **N**: This represents the normal force, acting vertically upward, perpendicular to the surface.
- **Mg**: This denotes the gravitational force (weight) acting downwards on the object, where *M* is the mass and *g* is the acceleration due to gravity.
- **f**: This is the frictional force acting horizontally to the left, opposing the motion of the object.
- **T**: This symbolizes the tension force acting on the object, directed diagonally upwards to the right.
- **θ**: This represents the angle between the tension force **T** and the horizontal axis.

The diagram helps in understanding how these forces interact and influence the motion and equilibrium of the object.

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