Read in one integer value, which I will call start for this explanation.Ensure that start is between 5 and 100, including those values. Include proper prompts for both the initial entry and in case of an error.The following loop will execute start number of times;Beginning with the start value entered, decrement the loop_step by 1 down to 1. Do not go to 0.If the current loop iteration value is even, an accumulator variable will be incremented by 1/loop_step. So, if the loop_step was 12, the accumulator variable would be incremented by 1/12.If the current loop iteration value is odd, the accumulator variable will be decremented by 1/loop_step. So, if the loop_step was 13, the accumulator variable would be decremented by ‑1/13.After the loop ends, print the value of the accumulator variable.

Language is not mentioned so C++ is used to solve the problem. Here, if statement is used to check…

Answered: he following loop will execute start…

Database System Concepts

7th Edition

ISBN:9780078022159

Author:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Publisher:Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan

Chapter1: Introduction

Section: Chapter Questions

Problem 1PE

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Read in one integer value, which I will call start for this explanation.

Ensure that start is between 5 and 100, including those values. Include proper prompts for both the initial entry and in case of an error.

The following loop will execute start number of times;

Beginning with the start value entered, decrement the loop_step by 1 down to 1. Do not go to 0.
If the current loop iteration value is even, an accumulator variable will be incremented by 1/loop_step. So, if the loop_step was 12, the accumulator variable would be incremented by 1/12.
If the current loop iteration value is odd, the accumulator variable will be decremented by 1/loop_step. So, if the loop_step was 13, the accumulator variable would be decremented by ‑1/13.

After the loop ends, print the value of the accumulator variable.

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