"he current flowing into a circuit from a battery with constant voltage Vx is shown below. If nergy absorbed between 2 and 5 minutes is 1080 J, Vx is (a-f): a) 15.0 V (b) 20.0 V (c) 36.0 V (d) 18.0 V (e) 72.0 V (f) 12.5 V Given that the battery's initial charge is 1530 mAh, and that the plot depicts the current drain rom the battery vs. time, the charge remaining in the battery after 6 minutes is (a-f): a) 930 mAh (b) 940 mAh (c) 1510 mAh (d)1520 mAh (e) 330 mAh (f) 340 mAh 600 300 Time (minutes) 3 4 5 6. -300 -600

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# Educational Transcription

## Current Flow in a Circuit

The problem involves analyzing the current flow into a circuit from a battery with a constant voltage \( V_X \). Based on the energy absorbed between 2 and 5 minutes, which is 1080 J, we need to determine \( V_X \) from the following options:

- (a) 15.0 V
- (b) 20.0 V
- (c) 36.0 V
- (d) 18.0 V
- (e) 72.0 V
- (f) 12.5 V

### Calculating Battery Charge

Given that the battery’s initial charge is 1530 mAh, and the plot below shows the current draining from the battery over time, we need to find the remaining charge in the battery after 6 minutes. The options are:

- (a) 930 mAh
- (b) 940 mAh
- (c) 1510 mAh
- (d) 1520 mAh
- (e) 330 mAh
- (f) 340 mAh

## Graph Analysis

### Plot Description

- **Axes**: The horizontal axis represents time in minutes (ranging from 0 to 6 minutes), and the vertical axis represents current in milliamperes (mA), ranging from -600 mA to 600 mA.
  
- **Plot**: The plot consists of bars representing current values for different time intervals. 
  - From 0 to 1 minute, the current is 300 mA.
  - From 1 to 2 minutes, the current increases to 600 mA.
  - From 2 to 3 minutes, the current drops back down to 300 mA.
  - From 3 to 4 minutes, the current decreases to 0 mA.
  - From 4 to 5 minutes, the current is at -300 mA, indicating charging.
  - From 5 to 6 minutes, the current returns to 0 mA.

### Annotations

- The schematic diagram on the left side of the graph shows a simple circuit with a battery and a component labeled "Circuit."

- Handwritten notes suggest calculations involving energy and charge relationships, (e.g., \( E = QV, \, Q = VI \)).

This exercise involves understanding the relationship between current
Transcribed Image Text:# Educational Transcription ## Current Flow in a Circuit The problem involves analyzing the current flow into a circuit from a battery with a constant voltage \( V_X \). Based on the energy absorbed between 2 and 5 minutes, which is 1080 J, we need to determine \( V_X \) from the following options: - (a) 15.0 V - (b) 20.0 V - (c) 36.0 V - (d) 18.0 V - (e) 72.0 V - (f) 12.5 V ### Calculating Battery Charge Given that the battery’s initial charge is 1530 mAh, and the plot below shows the current draining from the battery over time, we need to find the remaining charge in the battery after 6 minutes. The options are: - (a) 930 mAh - (b) 940 mAh - (c) 1510 mAh - (d) 1520 mAh - (e) 330 mAh - (f) 340 mAh ## Graph Analysis ### Plot Description - **Axes**: The horizontal axis represents time in minutes (ranging from 0 to 6 minutes), and the vertical axis represents current in milliamperes (mA), ranging from -600 mA to 600 mA. - **Plot**: The plot consists of bars representing current values for different time intervals. - From 0 to 1 minute, the current is 300 mA. - From 1 to 2 minutes, the current increases to 600 mA. - From 2 to 3 minutes, the current drops back down to 300 mA. - From 3 to 4 minutes, the current decreases to 0 mA. - From 4 to 5 minutes, the current is at -300 mA, indicating charging. - From 5 to 6 minutes, the current returns to 0 mA. ### Annotations - The schematic diagram on the left side of the graph shows a simple circuit with a battery and a component labeled "Circuit." - Handwritten notes suggest calculations involving energy and charge relationships, (e.g., \( E = QV, \, Q = VI \)). This exercise involves understanding the relationship between current
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