he common tangent BC of a reversed curve is 280.5 m and has a bearing of S47031’E. AB is the tangent of the first curve whose bearing is N38013’E . CD is a tangent of the second curve whose bearing is N72045’E. A is at the PC while D is at the PT. The radius of the first curve is 164 .41 m.. The V1 is at station 12 + 718.96. Find the stationing of th

Q: nd the common tangent is 310⁰. If the radius of the second curve is 150 m., determine the radius of…

A: Calculate the central angle of the first curve I1=310o-270oI1=40o

Q: 8. Determine the radius (in m.) of the second curve. (Final answer should be rounded-off to two…

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Q: Two tangents of a reverse curve have a back tangent of Due East and a forward tangent of S50°E. The…

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Q: Two tangents intersect at station 2+530. A compound curve laid on their tangents has the following…

A: *Multiple questions*   As per our guidelines we are supposed to answer?️ only one question. Kindly…

Q: A compound curve connects three tangents having azimuths of 254.24°, 270.01°, and 279.96°,…

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Q: Problem No. 1: Two tangents intersect at STA 2+550. A compound curve laid on their tangents has the…

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Q: the stationing of the PT.

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Q: A compound curve has a long chord that measures 250 m. The stations of the point of curvature and…

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Q: Two tangents intersect at station 2+530. A compound curve laid on their tangents has the following…

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Q: Problem 2. The common tangent BC of a reverse curve is 280.5 m and has a bearing of S 47°31′ E. AB…

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Q: 5. Compound Curve given elements: 1 = 20° D, = 4° Station of PC of compound curve = 8+ 120 2 = 25° D…

A:

Q: Given lines AB, BC, and CD, a reversed curve is to connect these three lines thus forming the…

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Q: The two converging tangents of a reverse curve intersect at 35⁰. This point of intersection is 150 m…

A: length of common tangent BD =150m   Radius of second Curve  R2=1720D=17206=286.67m   length of…

Q: The common tangent CD of a reversed curve is 280.5m and has an azimuth from the south (s)of 312°…

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Q: Situation 1: for the compound curve, the stations are shown. STATION PC PI PT 1+000 1+150 1+350…

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Q: The common tangent AB of a compound curve makes an angle with the tangents of the compound curve of…

A: Given: Angles made by the compound curves with the tangent are I1=25°30' and I2=30° respectively.…

Q: Situation 3] The bearing of the first tangent of a simple curve is N70.8°E while the second tangent…

A:

Q: The common tangent BC of a reversed curve is 280.5m and has a bearing of S47°31’E. AB is the tangent…

A: To Find the stationing of the PT.

Q: My REG NO= 5202 Question-1-B A compound curve is to consist of an arc of (Reg. No) m radius followed…

A: Radius of first arc = 5202 mRadius of second arc = 5202+400 = 5602 mIntersection angle of two…

Q: If the distance from V1 to PI of a compound curve is 200 m. And the angle at PCC between the 2 long…

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Q: 29. A simple curve connects two tangents AB and BC with bearing N 85°30' E and S 68°30'E…

A: A bend is only a circular segment which permit to interfaces two straight lines which are isolated…

Q: d backward tangent are N 65°30' E and N 75°40' W, respectively. If the curve is 2° for a full…

A: consider figure for solution (a) Degree of curve , D =2.0 deg       Radius  R = 5729.57/D=2864.785…

Q: for the compound, curve, the stations are shown. STATION PC PI PT 1+000 1+150 1+350 ote: Pl is the…

A: As we know, tangents are perpendicular to the radius, Line connecting PC to PI (PC-PI line) will…

Q: A 5° curve starts at station (5+432). The back and forward tangents of the curve have azimuths…

A: The degree of the curve is D=5∘. Calculate the deflection angle as follows. ∆=294037'-260040'=33∘57'…

Q: the stationing of the PT.

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Q: Two parallel tangents 20 m. apart are to be connected by a reversed curved. The distance between the…

A: It is given that distance between PC and PT is 160 m.  Distance between parallel tangents is 20 m…

Q: 3. The center line of two parallel tracks are connected by a reversed curve. The angle of…

A: Intersection angle of first curve, ∅1=15°Distance between the tracks, d=30 mRadius of the second…

Q: Two straights AV and BV intersect at chainage of 1252m. They are intercepted by a line MN 150m long…

A: Circular Curves: Whenever there is change in road alignment or railway alignment, there is need of…

Q: The common tangent AB of the compound curve is 76.42m, with an azimuth of 268030'. The vertex V…

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Q: Prob. 5 The length of the common tangent of a compound curve is 300 m. If the radii of the two…

A: Given:- length=300m radii of two curves=290 m & 740m central angle of first curve=420 To find:-…

Q: The common tangent BC of a reversed curve is 280.50m and has a bearing of S 47deg 31min E. AB is the…

A: Data given:Tangent of curve (BC) = 280.5 mBearing (BC)= S47ο31'EBearing of AB = N72ο45'EBearing of…

Q: A simple horizontal curve has 35 degrees of curvature and subtends an angle of 110 degrees. If the…

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Q: Situation 3] The bearing of the first tangent of a simple curve is N70.7ºE while the second tangent…

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Q: A 5° curve starts at station (5+432). The back and forward tangents of the curve have azimuths…

A: Given Degree of curve=5o The back and forward tangents of the curve have azimuths 260°40' and…

Q: The common tangent AB of a compound curve is 76.42m. with an azimuth of 268°30'. The vertex v being…

A:

Instruments for Surveying

Surveying is the practice that determines the relative three-dimensional positions of many different points on the earth’s surface. There are various instruments used in Surveying like Theodolites, Total station, Tripod stands, Plane table, etc. for measuring horizontal angle, vertical and sloping angle, which are very useful for giving accurate and precise measurement.