The common tangent BC of a reversed curve is 280.50m and has a bearing of S 47deg 31min E. AB is the tangent of the first curve whose bearing is N 72deg 45min E. CD is a tangent of the second curve whose bearing is N 38deg 13min E. A is at the PC while D is at the PT . The radius of the first curve is 180m . The PI1 is at Sta 12 + 523.37. Find the stationing of the PT 12 + 878.16 12 + 883.65 12 + 893.24 12 + 889.54 Please base your answer on the given choices thank you for the help
The common tangent BC of a reversed curve is 280.50m and has a bearing of S 47deg 31min E. AB is the tangent of the first curve whose bearing is N 72deg 45min E. CD is a tangent of the second curve whose bearing is N 38deg 13min E. A is at the PC while D is at the PT . The radius of the first curve is 180m . The PI1 is at Sta 12 + 523.37. Find the stationing of the PT 12 + 878.16 12 + 883.65 12 + 893.24 12 + 889.54 Please base your answer on the given choices thank you for the help
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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The common tangent BC of a reversed curve is 280.50m and has a bearing of S 47deg 31min E. AB is the tangent of the first curve whose bearing is N 72deg 45min E. CD is a tangent of the second curve whose bearing is N 38deg 13min E. A is at the PC while D is at the PT . The radius of the first curve is 180m . The PI1 is at Sta 12 + 523.37. Find the stationing of the PT
12 + 878.16
12 + 883.65
12 + 893.24
12 + 889.54
Please base your answer on the given choices thank you for the help
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