he average American gets a haircut every 40 days. Is the average different for college students? The data below shows the results of a survey of 14 college students asking them how many days elapse between haircuts. Assume that the distribution of the population is normal. 35, 53, 53, 50, 45, 38, 50, 37, 43, 33, 36, 33, 46, 49 What can be concluded at the the αα = 0.05 level of significance level of significance? For this study, we should use Select an answer t-test for a population mean z-test for a population proportion The null and alternative hypotheses would be: H0:H0: ? μ p Select an answer = > < ≠ H1:H1: ? μ p Select an answer > = ≠ < The test statistic ? z t = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 3 decimal places.) The p-value is ? > ≤ αα Based on this, we should Select an answer accept reject fail to reject the null hypothesis. Thus, the final conclusion is that ... The data suggest the population mean is not significantly different from 40 at αα = 0.05, so there is sufficient evidence to conclude that the population mean number of days between haircuts for college students is equal to 40. The data suggest the population mean number of days between haircuts for college students is not significantly different from 40 at αα = 0.05, so there is insufficient evidence to conclude that the population mean number of days between haircuts for college students is different from 40. The data suggest the populaton mean is significantly different from 40 at αα = 0.05, so there is sufficient evidence to conclude that the population mean number of days between haircuts for college students is different from 40.
he average American gets a haircut every 40 days. Is the average different for college students? The data below shows the results of a survey of 14 college students asking them how many days elapse between haircuts. Assume that the distribution of the population is normal. 35, 53, 53, 50, 45, 38, 50, 37, 43, 33, 36, 33, 46, 49 What can be concluded at the the αα = 0.05 level of significance level of significance? For this study, we should use Select an answer t-test for a population mean z-test for a population proportion The null and alternative hypotheses would be: H0:H0: ? μ p Select an answer = > < ≠ H1:H1: ? μ p Select an answer > = ≠ < The test statistic ? z t = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 3 decimal places.) The p-value is ? > ≤ αα Based on this, we should Select an answer accept reject fail to reject the null hypothesis. Thus, the final conclusion is that ... The data suggest the population mean is not significantly different from 40 at αα = 0.05, so there is sufficient evidence to conclude that the population mean number of days between haircuts for college students is equal to 40. The data suggest the population mean number of days between haircuts for college students is not significantly different from 40 at αα = 0.05, so there is insufficient evidence to conclude that the population mean number of days between haircuts for college students is different from 40. The data suggest the populaton mean is significantly different from 40 at αα = 0.05, so there is sufficient evidence to conclude that the population mean number of days between haircuts for college students is different from 40.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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he average American gets a haircut every 40 days. Is the average different for college students? The data below shows the results of a survey of 14 college students asking them how many days elapse between haircuts. Assume that the distribution of the population is normal.
35, 53, 53, 50, 45, 38, 50, 37, 43, 33, 36, 33, 46, 49
What can be concluded at the the αα = 0.05 level of significance level of significance?
- For this study, we should use Select an answer t-test for a population
mean z-test for a population proportion - The null and alternative hypotheses would be:
H0:H0: ? μ p Select an answer = > < ≠
H1:H1: ? μ p Select an answer > = ≠ <
- The test statistic ? z t = (please show your answer to 3 decimal places.)
- The p-value = (Please show your answer to 3 decimal places.)
- The p-value is ? > ≤ αα
- Based on this, we should Select an answer accept reject fail to reject the null hypothesis.
- Thus, the final conclusion is that ...
- The data suggest the population mean is not significantly different from 40 at αα = 0.05, so there is sufficient evidence to conclude that the population mean number of days between haircuts for college students is equal to 40.
- The data suggest the population mean number of days between haircuts for college students is not significantly different from 40 at αα = 0.05, so there is insufficient evidence to conclude that the population mean number of days between haircuts for college students is different from 40.
- The data suggest the populaton mean is significantly different from 40 at αα = 0.05, so there is sufficient evidence to conclude that the population mean number of days between haircuts for college students is different from 40.
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