HC3H5O2 <-> C3H5O2- + H+ Ka = 1.34 x 10-5. Propanoic Acid ionizes in water according to the equation above. 1. Calculate the pH of a 0.185 m solution of propanoic acid. 2. What is the resulting pH when enough sodium propanoate was added to make a 0.3 m solution (assume no change in volume).
HC3H5O2 <-> C3H5O2- + H+ Ka = 1.34 x 10-5. Propanoic Acid ionizes in water according to the equation above. 1. Calculate the pH of a 0.185 m solution of propanoic acid. 2. What is the resulting pH when enough sodium propanoate was added to make a 0.3 m solution (assume no change in volume).
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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HC3H5O2 <-> C3H5O2- + H+ Ka = 1.34 x 10-5. Propanoic Acid ionizes in water according to the equation above.
1. Calculate the pH of a 0.185 m solution of propanoic acid.
2. What is the resulting pH when enough sodium propanoate was added to make a 0.3 m solution (assume no change in volume).
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