H₂C CH3 cis-1,2-Dimethylcyclobutane H3C CH3 trans-1,3-Dimethylcyclobutane H3C H3C trans-1,2-Dimethylcyclobutane

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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I don't understand why the first one and second one are cis and trans respectively. Wouldn't the first one be trans-1,2-dimethylcyclobutane because the torsional strain wouldn't allow the carbons to be in the same conformation. Meaning one of the carbons would be up and then the next would be down and so on. Since both methyl groups are equatorial and the first and second carbons are arranged up and down, wouldn't it be trans. Same logic for the second molecule. Carbon 1, which is attached to the methyl is down, carbon 3 which is attached to the methyl should be down also because of torsional strain, and since both methyl are in axial (or equatorial?), it would be cis. Or is it based off of the way the carbons are positioned in the picture?
H₂C
CH3
cis-1,2-Dimethylcyclobutane
H3C
CH3
trans-1,3-Dimethylcyclobutane
H3C
H3C
trans-1,2-Dimethylcyclobutane
Transcribed Image Text:H₂C CH3 cis-1,2-Dimethylcyclobutane H3C CH3 trans-1,3-Dimethylcyclobutane H3C H3C trans-1,2-Dimethylcyclobutane
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