Having the below Nodal-Admittance Equation: j0.8 j1 FAAH! j2.5 2.5 V₂ j0.8 12.5 -j4.55 jo V3 1.5625 L-53° j1 j2.5 jo -j4.75 efter eliminating node 1 using successive elimination, The admittance connecting node 4 to neutral is: [-16.8 15 elect one: a. 14.456 Ob.j1.25 c.-13.089 Od.-j0.117 -j10 0 0 3.125 L36.87°

Introductory Circuit Analysis (13th Edition)
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ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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Having the below Nodal-Admittance Equation:
-j6.8 j5
j5
j0.8 j1
0
j0.8 j2.5
-j10 j2.5 2.5 V₂
-j4.55 jo
-4.75V, 3.125 36.87"
0
1.5625 L-53°
V3
j1 j2.5
jo
After eliminating node 1 using successive elimination, The admittance connecting node 4 to neutral is:
Select one:
O a. j4.456
O b.-j1.25
O c.-13.089
O d.-j0.117
Transcribed Image Text:Having the below Nodal-Admittance Equation: -j6.8 j5 j5 j0.8 j1 0 j0.8 j2.5 -j10 j2.5 2.5 V₂ -j4.55 jo -4.75V, 3.125 36.87" 0 1.5625 L-53° V3 j1 j2.5 jo After eliminating node 1 using successive elimination, The admittance connecting node 4 to neutral is: Select one: O a. j4.456 O b.-j1.25 O c.-13.089 O d.-j0.117
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