Hàu * 20 ⒸH₂ μ = 20 Hàu < 20 ⒸH₂ μ = 20 Hàu > 20 ⒸH: μ> 20 Hu<20 Find the test statistic and P-value. (Round your test statistic to one decimal place and your P-value to three decimal places.) t = P-value = State your conclusion. O We reject H. We do not have convincing evidence that the mean wrist extension for all people using the new mouse design is greater than 20 degrees. O We reject Ho. We have convincing evidence that the mean wrist extension for all people using the new mouse design is greater than 20 degrees. O We fail to reject H. We have convincing evidence that the mean wrist extension for all people using the new mouse design is greater than 20 degrees. O We fail to reject H. We do not have convincing evidence that the mean wrist extension for all people using the new mouse design is greater than 20 degrees.
Hàu * 20 ⒸH₂ μ = 20 Hàu < 20 ⒸH₂ μ = 20 Hàu > 20 ⒸH: μ> 20 Hu<20 Find the test statistic and P-value. (Round your test statistic to one decimal place and your P-value to three decimal places.) t = P-value = State your conclusion. O We reject H. We do not have convincing evidence that the mean wrist extension for all people using the new mouse design is greater than 20 degrees. O We reject Ho. We have convincing evidence that the mean wrist extension for all people using the new mouse design is greater than 20 degrees. O We fail to reject H. We have convincing evidence that the mean wrist extension for all people using the new mouse design is greater than 20 degrees. O We fail to reject H. We do not have convincing evidence that the mean wrist extension for all people using the new mouse design is greater than 20 degrees.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Question

Transcribed Image Text:**Title: Statistical Analysis of Wrist Extension Using a New Mouse Design**
**Introduction:**
Medical research indicates that repeated wrist extension beyond 20 degrees can increase the risk of wrist and hand injuries. This study involves 24 university students using a new computer mouse design to record each student’s wrist extension. The provided data aligns with summary values from a paper. The objective is to test the hypothesis that the mean wrist extension using the new mouse design exceeds 20 degrees. The analysis will use a sample mean of 25.75, a standard deviation of 1.870829, and a significance level of α = 0.05.
**Data:**
Wrist extension measurements (in degrees):
27, 25, 26, 28, 27, 24, 24, 26, 26, 26, 24, 25, 22, 24, 26, 31, 24, 25, 31, 24, 25, 27, 27, 24
**Hypotheses:**
State the appropriate null and alternative hypotheses:
1. \(H_0: \mu < 20\)
\(H_a: \mu > 20\)
2. \(H_0: \mu = 20\)
\(H_a: \mu \neq 20\)
3. \(H_0: \mu = 20\)
\(H_a: \mu < 20\)
4. \(H_0: \mu = 20\)
\(H_a: \mu > 20\)
**Calculations:**
Find the test statistic and P-value. (Round your test statistic to one decimal place and your P-value to three decimal places.)
- Test statistic (\(t\)): _____
- P-value: _____
**Conclusion:**
State your conclusion based on the test results:
- \(We\) reject \(H_0\). We do not have convincing evidence that the mean wrist extension for all people using the new mouse design is greater than 20 degrees.
- \(We\) reject \(H_0\). We have convincing evidence that the mean wrist extension for all people using the new mouse design is greater than 20 degrees.
- \(We\) fail to reject \(H_0\). We have convincing evidence that the mean wrist extension for all people using the new mouse design is greater than 20
Expert Solution

Step 1: Given:
Number of students(n)=24
Sample mean=25.75
sample satandard deviation=1.870829
Step by step
Solved in 3 steps with 3 images

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