Cars of customers who experienced a decreased overall life of tires underwent a pressure check. The pressure inspection test had possible outcome labelled as too high (H), too low (L), or normal (N). Checking the two front wheels simultaneously (and not distinguishing between left and right) results in the six possible outcomes {HH, LL, NN, HL, HN, LN}. If the probabilities for the single wheel are: P(H) = 0₁, P(L) = 02, P(N) = 1−01 - 0₂ and the two wheels are independent of each other (questionable assumption...), the probabilities of the six outcomes for a randomly selected car are the following:
Cars of customers who experienced a decreased overall life of tires underwent a pressure check. The pressure inspection test had possible outcome labelled as too high (H), too low (L), or normal (N). Checking the two front wheels simultaneously (and not distinguishing between left and right) results in the six possible outcomes {HH, LL, NN, HL, HN, LN}. If the probabilities for the single wheel are: P(H) = 0₁, P(L) = 02, P(N) = 1−01 - 0₂ and the two wheels are independent of each other (questionable assumption...), the probabilities of the six outcomes for a randomly selected car are the following:
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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if able please provide some explanation with the taken steps in the exercise attached image. Thank you in advance

Transcribed Image Text:Cars of customers who experienced a decreased overall life of tires underwent a pressure check. The
pressure inspection test had possible outcome labelled as too high (H), too low (L), or normal (N).
Checking the two front wheels simultaneously (and not distinguishing between left and right) results
in the six possible outcomes {HH, LL, NN, HL, HN, LN}. If the probabilities for the single wheel
are:
P(H) = 0₁, P(L) = 02, P(N) = 1-01 - 0₂
and the two wheels are independent of each other (questionable assumption...), the probabilities of
the six outcomes for a randomly selected car are the following:
T₁ = P(HH) = 0², 7₂ = P(LL) = 02₂, 73= P(NN) = (1 - 0₁ - 0₂)²,
==
T4 := P(HL) = 20102, 5:= = P(HN) 201 (1-01-02), 76 = = P(LN) = 20₂(1 – 01-02)
The collected data during the inspection can be summarized by the following table:
(a)
(b)
=
Outcome HH LL NN HL HN LN
Frequency 50 27 15 18 51 37
Given the data, find the Maximum Likelihood estimate of (01,02)
Test at the 0.05 significance level the hypotheses:
Ho P1= 1, P2 = 2,...,P6 = 76,
H₁ the hypothesis Ho is not true.
:
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