A large clinical trial of the effect of diet on breast cancer assigned women at random to either a normaldiet or a low-fat diet. To check that the random assignment did produce comparable groups, we cancompare the two groups at the start of the study. Asked if there is a family history of breast cancer: 1276 ofthe 5964 women in the low-fat group and 1507 of the 7726 women in the control group said "Yes." If therandom assignment worked well, there should not be a significant difference in the proportions with afamily history of breast cancer. How significant is the observed difference? State: Is there evidence of adifference in the proportion of women with a family history of breast cancer between the treatment andcontrol groups? Plan: Let pi be the proportion for the treatment group, and Pz the proportion for thecontrol group. State the hypotheses for your test.Ha:Pi + P2 Solve: Give the value of the test statistic. Use the calculator. Select an answer ♥Ho:pi = p2What is the P-value for the test?What do you conclude?O There is evidence that the two proportions differ at the 0.10 significance level..O The difference between the sample proportions is not significant at the 0.10 level.O The data prove that the null hypothesis is true. That is, the randomization worked.

Given: Number of women in low fat group said yes is, x1=1276 Number of women in low fat group,…

Ha:P1 # P2 Solve: Give the value of the test statistic. Use the calculator. Select an answer What do you conclude? What is the P-value for the test? There is evidence that the two proportions differ at the 0.10 significance level. O The difference between the sample proportions is not significant at the 0.10 level. O The data prove that the null hypothesis is true. That is, the randomization worked.