Handy Glass Pty has found that 25% of customers in its client base are located in Gauteng. A sample of 130 customers is randomly selected. Assuming normal distribution: Q.2.1.2 What is the probability that more than 24.50% of the customers in the sample are situated in Gauteng? Interpret your answer.
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Handy Glass Pty has found that 25% of customers in its client base are located in
Gauteng. A sample of 130 customers is randomly selected. Assuming
distribution
sample are situated in Gauteng? Interpret your answer.
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- Suppose a group is interested in determining whether teenagers obtain their drivers license at approximately the same average age across the country. Five teenagers from each region of the country were randomly selected. The data collected is their age at which the teenagers obtained their drivers licenses and is summarized in the table below. Test the hypothesis that the five regions produce the same mean average for a teenage driver’s license. Northeast South West Central East 16.3 16.9 16.4 16.2 17.1 16.1 16.5 16.5 16.6 17.2 16.4 16.4 16.6 16.5 16.6 16.5 16.2 16.1 16.4 16.8 (a)What are the hypotheses? (b)What is the F – Statistic? (c) What is the p – value? (d) What can you conclude about the null hypothesis? (e) What can you conclude about the population means?ath ess Most Watched Ani... A pharmaceutical company claims their new diabetes medication results in less variance in a patient's glucose level than if the patient were on no medication at all. An endocrinologist wishes to test this claim. She divides participants randomly into two groups. Group A consists of 20 diabetics who received the medication; group B consists of 26 diabetics who received a placebo. After two weeks, the blood sugar level of each patient in each group was measured with the following results (in mg/dL): Group A: 77.8, 229.4, 199.9, 110.1, 180.2, 116.1, 139.7, 171.1, 37.4, 158.1, 88.4, 195.5, 246.1, 142.4, 178.1, 105.5, 179.6, 146.1, 78.8, 123.7 Group B: 124.5, 130.1, 136, 162.8, 113.4, 72.8, 142.6, 50.3, 179.8, 197, 230, 194.3, 171, 109.3, 114.4, 107.5, 114.7, 195.3, 127.7, 126.4, 85.6, 166.7, 182.3, 113.5, 216.7, 162.8 Ho: Perform a hypothesis test using a 6% level of significance to test the pharmaceutical company's claim. Step 1: State the null and alternative…The mean number of sick days an employee takes per year is believed to be about 10. Members of a personnel department do not believe this figure. They randomly survey 8 employees. The number of sick days they took for the past year are as follows: 10; 5; 13; 3; 11; 8; 6; 9. Let X = the number of sick days they took for the past year. Should the personnel team believe that the mean number is about 10? Conduct a hypothesis test at the 5% level.Note: If you are using a Student's t-distribution for the problem, you may assume that the underlying population is normally distributed. (In general, you must first prove that assumption, though.) What is the test statistic? (If using the z distribution round your answers to two decimal places, and if using the t distribution round your answers to three decimal places.) t = Construct a 95% confidence interval for the true mean. Sketch the graph of the situation. Label the point estimate and the lower and upper bounds of the confidence…
- A university wanted to see whether there was a significant difference in age between its day staff and evening staff. A random sample of 35 staff members is selected from each group. The data are given below. Test the hypothesis that there is no difference in age between the two groups. Use a =0.05. Day Staff 22 24 24 23 19 19 23 22 18 21 21 18 18 25 29 24 23 22 22 21 20 20 20 27 17 19 18 21 20 23 26 30 25 21 25 Evening Staff 18 23 25 23 21 21 23 24 27 31 24 20 20 23 19 25 24 27 23 20 20 21 25 24 23 28 20 19 23 24 20 27 21 29 30Handy Glass Pty has found that 25% of customers in its client base are located in London. A sample of 130 customers is randomly selected. Assuming normal distribution:Q.2.1.1 Determine the standard error for this sample. Q.2.1.2 What is the probability that more than 24.50% of the customers in thesample are situated in London? Interpret your answer.A researcher selects a sample of 6 men and 11 women. She asks participants to rate the likelihood they would do female-stereotyped jobs (such as nursing or school teaching) on a scale from 1 = not likely at all to 5 = very likely. Men indicated that they would be less likely to do these jobs (M = 2.1) compared with women (M = 4.3). What is the weighted mean for the combined sample of 17 total participants? O O 2.1 4.3 3.2 3.5
- An article about the California lattery gave the following information on the age distribution of adults in California: 35% are between 18 and 34 years old, 51% are between 35 and 64 years old, and 14% are 65 years old or older. The artide also gave Information on the age distribution of those who purchase lottery tickets. The following table is consistent with the values given in the article. Suppose that the data resulted from a random sample of 200 lattery ticket purchasers. Based on these sample data, is it reasonable to condude that ane or more af these three age groups buys a disproportionate share of lottery tickets? Use a chi-square goodness-of-fit test with a- 0.05. (Round your answer to two decimal places.) Age of Purchaser Frequency 18-34 45 35-64 100 65 and over 55 P-value interval OpA regional transit authority is concerned about the number of riders on one of its bus routes. In setting up the route, the assumption is that the number of riders is the same on every day from Monday through Friday. A random sample of 100 riders yielded the following results: Day Monday Tuesday Wednesday Thursday Friday Using a = 10%, determine whether the transit authority's assumption is correct. Number of Riders 20 15 30 17 162 Define the random variable, its type of distribution, and compute for the variable/measure that is being asked. You can follow the example belowUsing a pooled sample estimator, o , assumes the two populations have O A. different means. O B. the same mean. O C. the same variance. O D. different variances.The type of household for the U.S. population and for a random sample of 411 households from a community in Montana are shown below. Observed Number of Households in the Community Percent of U.S. Type of Household Households Married with children 26% 110 Married, no children Single parent One person Other (e.g., roommates, siblings) 29% 101 32 25% 98 11% 70 Use a 5% level of significance to test the claim that the distribution of U.S. households fits the Dove Creek distribution. (a) What is the level of significance? State the nul and alternate hypotheses. O Ho: The distributions are different. H: The distributions are the same. O Hg: The distributions are the same. H: The distributions are different. O Hg: The distributions are the same. H: The distributions are the same. O Hg: The distributions are different. H: The distributions are different. (b) Find the value of the chi-square statistic for the sample. (Round the expected frequencies to two decimal places. Round the test…
