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Halle Leg en las terminales del circuito de la figura 6 mH 8 mH a o 5 mH 12 mH 8 mH 6 mH 4 mH bo ll 8 mH 10 mH

Halle Leg en las terminales del circuito de la figura 6 mH 8 mH a o 5 mH 12 mH 8 mH 6 mH 4 mH bo ll 8 mH 10 mH

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Halle Leg en las terminales del circuito de la figura 6 mH 8 mH a o 5 mH 12 mH 8 mH 6 mH 4 mH bo mm ell 8 mH 10 mH ll ell all
Transcribed Image Text:Halle Leg en las terminales del circuito de la figura 6 mH 8 mH a o 5 mH 12 mH 8 mH 6 mH 4 mH bo mm ell 8 mH 10 mH ll ell all
L, = 6+10+ 8||5||(8 +12) + 6||(8 +4)| = 16+8 (4 + 4) =16+4 Leg = 20 mH
Transcribed Image Text:L, = 6+10+ 8||5||(8 +12) + 6||(8 +4)| = 16+8 (4 + 4) =16+4 Leg = 20 mH
Expert Solution
Step 1

We need to find equivalent inductance between a and b.

We will use series and parallel combination of inductor to find equivalent inductance .

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