HA + NaOH → → NaA + H₂O Kelly split a 50.0 mL solution of weak acid into two separate 25.0 mL parts. She then added NaOH one of the parts until she observed the endpoint. After then added both parts, she measured the pH of the half-titrated weak acid solution as 8.70. What is the Ka for the acid? Ka = [?] x 10[?] Coefficient (green) Exponent (yellow) Enter
HA + NaOH → → NaA + H₂O Kelly split a 50.0 mL solution of weak acid into two separate 25.0 mL parts. She then added NaOH one of the parts until she observed the endpoint. After then added both parts, she measured the pH of the half-titrated weak acid solution as 8.70. What is the Ka for the acid? Ka = [?] x 10[?] Coefficient (green) Exponent (yellow) Enter
Introductory Chemistry: A Foundation
9th Edition
ISBN:9781337399425
Author:Steven S. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Donald J. DeCoste
Chapter16: Acids And Bases
Section: Chapter Questions
Problem 10ALQ
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Question
![HA + NaOH → → NaA + H₂O
Kelly split a 50.0 mL solution of weak acid into
two separate 25.0 mL parts. She then added
NaOH one of the parts until she observed the
endpoint. After then added both parts, she
measured the pH of the half-titrated weak
acid solution as 8.70.
What is the Ka for the acid?
K₂ = [? ] × 10¹²]
a
Coefficient (green)
Exponent (yellow)
Enter](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa4c65346-a6bd-47be-a891-a239e86f6fd1%2F822f2052-6ce5-4eae-b653-842110771a58%2Fb605o9e_processed.jpeg&w=3840&q=75)
Transcribed Image Text:HA + NaOH → → NaA + H₂O
Kelly split a 50.0 mL solution of weak acid into
two separate 25.0 mL parts. She then added
NaOH one of the parts until she observed the
endpoint. After then added both parts, she
measured the pH of the half-titrated weak
acid solution as 8.70.
What is the Ka for the acid?
K₂ = [? ] × 10¹²]
a
Coefficient (green)
Exponent (yellow)
Enter
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