HA is a weak acid. B1 and B2 are weak bases. Two acid/base neutralization experiments are performed and the pH values of the resulting solutions are reported below. Experiment 1. 0.45 mol weak acid HA and 0.45 mol weak base B1 are mixed into 1-L solution. The pH of the resulting solution is 5.87. Experiment 2. 0.45 mol weak acid HA and 0.45 mol weak base B2 are mixed into 1-L solution. The pH of the resulting solution is 9.24. Which of the following is correct about HA, B1 and B2? Choose one option only Options: a. Kb(B1) < Kb (B2) b. Kb(B1) > Kb (B2) c. Ka(HA) > Kb(B2)
HA is a weak acid. B1 and B2 are weak bases. Two acid/base neutralization experiments are performed and the pH values of the resulting solutions are reported below. Experiment 1. 0.45 mol weak acid HA and 0.45 mol weak base B1 are mixed into 1-L solution. The pH of the resulting solution is 5.87. Experiment 2. 0.45 mol weak acid HA and 0.45 mol weak base B2 are mixed into 1-L solution. The pH of the resulting solution is 9.24. Which of the following is correct about HA, B1 and B2? Choose one option only Options: a. Kb(B1) < Kb (B2) b. Kb(B1) > Kb (B2) c. Ka(HA) > Kb(B2)
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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HA is a weak acid. B1 and B2 are weak bases. Two acid/base neutralization experiments are performed and the pH values of the resulting solutions are reported below.
Experiment 1. 0.45 mol weak acid HA and 0.45 mol weak base B1 are mixed into 1-L solution. The pH of the resulting solution is 5.87.
Experiment 2. 0.45 mol weak acid HA and 0.45 mol weak base B2 are mixed into 1-L solution. The pH of the resulting solution is 9.24.
Which of the following is correct about HA, B1 and B2?
Choose one option only
Options:
a. Kb(B1) < Kb (B2)
b. Kb(B1) > Kb (B2)
c. Ka(HA) > Kb(B2)
d. None of the above
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