A patient is suspected of having low stomach acid, a condition known as hypochloridia. To determine whether the patient hasthis condition, her doctors take a 15.00 mL sample of her gastric juices and titrate the sample with 1.27 x 10-4 M KOH. Thegastric juice sample required 24.7 mL of the KOH titrant to neutralize it.Calculate the pH of the gastric juice sample. ASsume the sample contained no ingested food or drink which might otherwiseinterfere with the titration.pH =* TOOLSx10For theypochloridia, the pH of the gastric juices from the stomach must be greater than pH 4.Does the patient have hypochloridia?unable to determinenoyesO O O

A doctor titrate 15.00 mL of gastric juice with 24.7 mL of 1.27×10-4 M KOH solution. We have to find…

Answered: A patient is suspected of having low…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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A patient is suspected of having low stomach acid, a condition known as hypochloridia. To determine whether the patient has
this condition, her doctors take a 15.00 mL sample of her gastric juices and titrate the sample with 1.27 x 10-4 M KOH. The
gastric juice sample required 24.7 mL of the KOH titrant to neutralize it.
Calculate the pH of the gastric juice sample. ASsume the sample contained no ingested food or drink which might otherwise
interfere with the titration.
pH =
* TOOLS
x10
For the
ypochloridia, the pH of the gastric juices from the stomach must be greater than pH 4.
Does the patient have hypochloridia?
unable to determine
no
yes
O O O

Expert Solution

Step 1

A doctor titrate 15.00 mL of gastric juice with 24.7 mL of $1.27 \times 10^{- 4} M$ KOH solution.

We have to find the pH of gastric juice.Gastric juice contain mainly HCl

The reaction that will take place is

$K O H + H C l \to K C l + H_{2} O$

Recall the following expression

$(V_{1}) \times (M_{1}) = (V_{2}) \times (M_{2}) V o l u m e o f g a s t r i c e j u i c e (V_{1}) = 15.00 m L C o n c e n t r a t i o n o f g a s t r i c j u i c e = M_{2} V o l u m e o f K O H (V_{2}) = 24.7 m L C o n c e n t r a t i o n o f g a s t r i c j u i c e (M_{1}) = 1.27 \times 10^{- 4} M$

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