H3C-CI+ NaCN DMSO Identify the nucleophile in the following reaction. H3C-CN + NaCl A) Methyl chloride (CH3CI) B) DMSO C) Chloride Ion (CI-) D) Sodium lon (Na+) E) Cyanide lon (CN-)
H3C-CI+ NaCN DMSO Identify the nucleophile in the following reaction. H3C-CN + NaCl A) Methyl chloride (CH3CI) B) DMSO C) Chloride Ion (CI-) D) Sodium lon (Na+) E) Cyanide lon (CN-)
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Identify the Nucleophile in the Following Reaction:**
In the provided reaction, methyl chloride (CH₃Cl) reacts with sodium cyanide (NaCN) in the presence of DMSO to form acetonitrile (CH₃CN) and sodium chloride (NaCl).
**Reaction:**
\[ \text{H}_3\text{C} - \text{Cl} + \text{NaCN} \xrightarrow{\text{DMSO}} \text{H}_3\text{C} - \text{CN} + \text{NaCl} \]
**Choices:**
A) Methyl chloride (CH₃Cl)
B) DMSO
C) Chloride Ion (Cl⁻)
D) Sodium Ion (Na⁺)
E) Cyanide Ion (CN⁻)
**Explanation:**
The task is to identify the nucleophile in this reaction, which is the species donating an electron pair to form a chemical bond during the reaction.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F48d77f89-4a4a-4be1-888e-697d04354f4d%2Fae2bf1f1-a0a7-4827-8939-8b92cd1e866f%2Frafxhi_processed.png&w=3840&q=75)
Transcribed Image Text:**Identify the Nucleophile in the Following Reaction:**
In the provided reaction, methyl chloride (CH₃Cl) reacts with sodium cyanide (NaCN) in the presence of DMSO to form acetonitrile (CH₃CN) and sodium chloride (NaCl).
**Reaction:**
\[ \text{H}_3\text{C} - \text{Cl} + \text{NaCN} \xrightarrow{\text{DMSO}} \text{H}_3\text{C} - \text{CN} + \text{NaCl} \]
**Choices:**
A) Methyl chloride (CH₃Cl)
B) DMSO
C) Chloride Ion (Cl⁻)
D) Sodium Ion (Na⁺)
E) Cyanide Ion (CN⁻)
**Explanation:**
The task is to identify the nucleophile in this reaction, which is the species donating an electron pair to form a chemical bond during the reaction.
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