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H2O   +   H2O   ⇔     H3O+1   +   OH-1               [H3O+1][OH-1]     Kw = ––––––––––––– =  [H3O+1][OH-1] = (1 x 10-7)2 = 1 x 10-14               [H2O]2

H2O   +   H2O   ⇔     H3O+1   +   OH-1               [H3O+1][OH-1]     Kw = ––––––––––––– =  [H3O+1][OH-1] = (1 x 10-7)2 = 1 x 10-14               [H2O]2

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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H2O   +   H2O   ⇔     H3O+1   +   OH-1    

          [H3O+1][OH-1]    

Kw = ––––––––––––– =  [H3O+1][OH-1] = (1 x 10-7)2 = 1 x 10-14

              [H2O]2

The inverse logarithm, or -log, of [H3O*1][OH1] = 10-14 is pH + pOH = 14 1. What happens to the [H30*1] when base is added to neutral water ? the [H3O*'] goes 2. What happens to the pH when base is added to neutral water ? an example of a decreased [H30*1] is [H3O*l] = 1 x 108. Thus pH = -log[108] = thus, adding acid makes the pH go 3. What happens to the [H3O*1] when base is added to neutral water ? in the equation [H30*'][OH'] = 1014, when [OH'] increases, the [H3O+11 goes 4. What happens to the pOH when base is added to neutral water ? when [OH] increases, the pOH goes since the pOH = -log[OH1] this can also be seen using pH + pOH = 14 5. What happens to the Kw when base is added to neutral water ? because it's a constant. a. down b. up c. no change
Transcribed Image Text:The inverse logarithm, or -log, of [H3O*1][OH1] = 10-14 is pH + pOH = 14 1. What happens to the [H30*1] when base is added to neutral water ? the [H3O*'] goes 2. What happens to the pH when base is added to neutral water ? an example of a decreased [H30*1] is [H3O*l] = 1 x 108. Thus pH = -log[108] = thus, adding acid makes the pH go 3. What happens to the [H3O*1] when base is added to neutral water ? in the equation [H30*'][OH'] = 1014, when [OH'] increases, the [H3O+11 goes 4. What happens to the pOH when base is added to neutral water ? when [OH] increases, the pOH goes since the pOH = -log[OH1] this can also be seen using pH + pOH = 14 5. What happens to the Kw when base is added to neutral water ? because it's a constant. a. down b. up c. no change
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