i need the answer quickly H.W.(2): For the A-connectedload in Figure, find the linevoltages, phase currents andline currents. Draw the phasordiagram.Va = 16 kV 20eV = 16 kV -120= 16 kV 2+1201020 1E0.3 k2,ECA+]10 120 0Ege0.3 k0.3 kI k[Answer:]10 !20 2(a) L = 15.33 A Z-73.30°, (b) I = 26.55 A L-103.30°, (c) EAB = 17.01 kV Z-0.59°,I = 26.55 A Z136.70°,Ic = 26.55 A Z16.70°I = 15.33 A Z-193.30°,Ica = 15.33 A Z46.7°Epc = 17.01 kV 2-120.59°,EcA = 17.01 kV Z119.41°%3D

Answered: Image /qna-images/answer/d2cc7906-f2dd-46df-87fd-079580850936.jpg

H.W.(2): For the A-connected load in Figure, find the line voltages, phase currents and line currents. Draw the phasor diagram. = 16KV 20 V= 16V L-120 V- 16KV 2+120 101! 20 03 k Eca 100 200 Eg 03 k 0.3 kf [Answer:] 10 2012 I = 15.33 A Z-193.30°, La = 15.33 A Z46.7° (a) L= 15.33 A Z-73.30°, (b) L= 26.55 A L-103.30°, (c) EAR = 17.01 kV Z-0.59°. I = 26.55 A Z136.70°, Ia = 26.55 A Z16.70° Egc = 17.01 kV Z-120.59°, Eca = 17.01 kV Z119.41° %3! %3D %3D %3!

H.W.(2): For the A-connected load in Figure, find the line voltages, phase currents and line currents. Draw the phasor diagram. = 16KV 20 V= 16V L-120 V- 16KV 2+120 101! 20 03 k Eca 100 200 Eg 03 k 0.3 kf [Answer:] 10 2012 I = 15.33 A Z-193.30°, La = 15.33 A Z46.7° (a) L= 15.33 A Z-73.30°, (b) L= 26.55 A L-103.30°, (c) EAR = 17.01 kV Z-0.59°. I = 26.55 A Z136.70°, Ia = 26.55 A Z16.70° Egc = 17.01 kV Z-120.59°, Eca = 17.01 kV Z119.41° %3! %3D %3D %3!

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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