H.W: A frame ABC is supported in part by cable DBE that passes through a frietionless ring at B. Knowing that the tension in the cable is 385 N, determine (a)- the resultant ( R) of the forces as a vector which exerted by the cables on the support at D and E, (b)- the angles between R and each of the coordinate axes. Answer: 2 mm 210 R= Fn + F =-(375 N)i + (455 N)j-(460 N)k 0, =120.1° 0, = 52.5° S10 mm 400 m 0, =128.0° 40 mm
H.W: A frame ABC is supported in part by cable DBE that passes through a frietionless ring at B. Knowing that the tension in the cable is 385 N, determine (a)- the resultant ( R) of the forces as a vector which exerted by the cables on the support at D and E, (b)- the angles between R and each of the coordinate axes. Answer: 2 mm 210 R= Fn + F =-(375 N)i + (455 N)j-(460 N)k 0, =120.1° 0, = 52.5° S10 mm 400 m 0, =128.0° 40 mm
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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
Transcribed Image Text:H.W:
A frame ABC is supported in part by cable DBE that passes through a frictionless ring at B. Knowing that the
tension in the cable is 385 N, determine (a)- the resultant (R) of the forces as a vector which exerted by the
cables on the support at D and E, (b)- the angles between R and each of the coordinate axes.
Answer:
20 mm
10 mn
R= Fan + FRE =-(375 N)i +(455 N)j-(460 N)k
E
0, =120.1° «
0, = 52.5° 4
510 mm
400 mm
0. =128.0° 4
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