H.W . solution Example (1 15)For the network of fig (1 35) if VGS = 2.2 v and Ip = 2.03 mA find Zi , Zo , Av , Vo ?VDD = 12VRD3.6KOVoIpss = 10mAVP = -4 vYoş-50uRs1.1kaVi40mAFig (1 33) AMP of exanrd + RDZ = RS |/1+ gm rd1rd =yos+ 20ka50µ%3DVGS2 Ipss|VP|(-2.2v)1 -(1 – 4)2 x 10mgm == 2.25 m S420k + 3.6kZi = 1.1 k //= 1.1k // 0.51k = 0.35kN1+ (2.25m)(20kN)Zo = RD //rd = 3.6// 20 = 3.05kQRDgm RD +3.6k(2.25m)(3.6 k) +20krdRD1+rdAv == 7.02%3D3.6k1+ 20kVoAv = VVo = Av.Vi = (7.02)(40m) = 280.8mVH.W (1 17)For the network of example (1_15) find Ai if a resistor of RL = 1KN is connected to the o/p terminals.(ANS / Ai = -3.26)

We need to find out current Gain for given circuit .

Answered: H.W (1 17) For the network of example…

H.W (1 17) For the network of example (1_15) find Ai if a resistor of RL = 1KN is connected to the o/p terminals. (ANS /Ai =-3.26)

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

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Concept explainers

Electrical Heating Unit

The conversion of electrical energy to heat energy is known as electric heating. The heating system that converts the electrical energy to heat energy for various application is called electrical heating unit. Electricity is employed as the firing mechanism in electric heating systems, which transforms electric current to heat. Electric heaters have heating elements in the form of electric resistors.

Question

H.W . solution

Example (1 15)
For the network of fig (1 35) if VGS = 2.2 v and Ip = 2.03 mA find Zi , Zo , Av , Vo ?
VDD = 12V
RD
3.6KO
Vo
Ipss = 10mA
VP = -4 v
Yoş-50u
Rs
1.1ka
Vi
40mA
Fig (1 33) AMP of exan
rd + RD
Z = RS |/
1+ gm rd
1
rd =
yos
+ 20ka
50µ
%3D
VGS
2 Ipss
|VP|
(-2.2v)
1 -
(1 – 4)
2 x 10m
gm =
= 2.25 m S
4
20k + 3.6k
Zi = 1.1 k //
= 1.1k // 0.51k = 0.35kN
1+ (2.25m)(20kN)
Zo = RD //rd = 3.6// 20 = 3.05kQ
RD
gm RD +
3.6k
(2.25m)(3.6 k) +
20k
rd
RD
1+
rd
Av =
= 7.02
%3D
3.6k
1+ 20k
Vo
Av = V
Vo = Av.Vi = (7.02)(40m) = 280.8mV
H.W (1 17)
For the network of example (1_15) find Ai if a resistor of RL = 1KN is connected to the o/p terminals.
(ANS / Ai = -3.26)

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