A rectangular loop of wire with sides 0.144 and 0.471 m lies in a plane perpendicular to a constant magnetic field (see part a of the drawing). The magnetic field has a magnitude of 0.882 T and is directed parallel to the normal of the loop's surface. In a time of 0.135 s, one-half of the loop is then folded back onto the other half, as indicated in part b of the drawing. Determine the magnitude of the average emf induced in the loop.
- According to Faraday's law of induction, any change in magnetic environment will cause a production of induced emf,
that is, = - ......................1
where represents rate of change of magnetic flux.
where = BxA = BA sin ..............2
B is external magnetic field
A is area of cross section.
Trending now
This is a popular solution!
Step by step
Solved in 2 steps with 1 images
