In the figure below, the current in the long, straight wire is I, 6.10 A, and the wire lies in the plane of the rectangular loop, which carries 14.2 A. The dimensions shown are c= 0.100 m, a 0.150 m, and = 0.450 m. Find the magnitude and direction of the net force exerted by the magnetic field due to the straight wire on the loop. magnitude N direction to the right x 10

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Chapter1: Units, Trigonometry. And Vectors
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Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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### Transcription for Educational Use

**Problem Statement:**

In the figure below, the current in the long, straight wire is \( I_1 = 6.10 \, \text{A} \), and the wire lies in the plane of the rectangular loop, which carries \( 14.2 \, \text{A} \). The dimensions shown are \( c = 0.100 \, \text{m} \), \( a = 0.150 \, \text{m} \), and \( \ell = 0.450 \, \text{m} \). Find the magnitude and direction of the net force exerted by the magnetic field due to the straight wire on the loop.

**Inputs:**

- **Magnitude:** (Field to input value)
- **Direction:** (Dropdown options: to the right, to the left, into the page, out of the page)

### Diagram Explanation:

- The diagram shows a long, straight wire on the left carrying a current \( I_1 \), directed upward.
- Adjacent to the straight wire, there's a rectangular loop carrying a current \( I_2 \), also directed upward on the left side of the loop.
- The dimensions of the system are labeled as:
  - \( a = 0.150 \, \text{m} \) (horizontal distance between the straight wire and the nearest side of the loop)
  - \( c = 0.100 \, \text{m} \) (width of the loop)
  - \( \ell = 0.450 \, \text{m} \) (vertical height of the loop)

The task is to calculate the net magnetic force and its direction on the loop due to the current in the straight wire.
Transcribed Image Text:### Transcription for Educational Use **Problem Statement:** In the figure below, the current in the long, straight wire is \( I_1 = 6.10 \, \text{A} \), and the wire lies in the plane of the rectangular loop, which carries \( 14.2 \, \text{A} \). The dimensions shown are \( c = 0.100 \, \text{m} \), \( a = 0.150 \, \text{m} \), and \( \ell = 0.450 \, \text{m} \). Find the magnitude and direction of the net force exerted by the magnetic field due to the straight wire on the loop. **Inputs:** - **Magnitude:** (Field to input value) - **Direction:** (Dropdown options: to the right, to the left, into the page, out of the page) ### Diagram Explanation: - The diagram shows a long, straight wire on the left carrying a current \( I_1 \), directed upward. - Adjacent to the straight wire, there's a rectangular loop carrying a current \( I_2 \), also directed upward on the left side of the loop. - The dimensions of the system are labeled as: - \( a = 0.150 \, \text{m} \) (horizontal distance between the straight wire and the nearest side of the loop) - \( c = 0.100 \, \text{m} \) (width of the loop) - \( \ell = 0.450 \, \text{m} \) (vertical height of the loop) The task is to calculate the net magnetic force and its direction on the loop due to the current in the straight wire.
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