my teacher told me the answer was 4a⁷b⁶ because of the product of a power how can I tell the truth us there any laws in math please provide the law to correct her ty GUIDED PRACTICEApply the laws of exponents in each.1. (4a³b²)(-2a²b²)2 Product of a PowerConsider the expression 2'-2' using the definition ofexponents2'-2 = (2-2-2)(2-2-2-2-2)=2Thus, 2-2-2.=23+5=2"

We will solve (4a3b2)(-2a2b2)2 step by step using the laws of exponents. Step 1: Expand…

GUIDED PRACTICE Apply the laws of exponents in each. 1. (4a³b²)(-2a²b²)2 Product of a Power Consider the expression 2'-2' using the definition of exponents 2'-2 = (2-2-2)(2-2-2-2-2)=2 Thus, 2-2-2. =23+5 =2"

GUIDED PRACTICE Apply the laws of exponents in each. 1. (4a³b²)(-2a²b²)2 Product of a Power Consider the expression 2'-2' using the definition of exponents 2'-2 = (2-2-2)(2-2-2-2-2)=2 Thus, 2-2-2. =23+5 =2"

Elementary Algebra

17th Edition

ISBN:9780998625713

Author:Lynn Marecek, MaryAnne Anthony-Smith

Publisher:Lynn Marecek, MaryAnne Anthony-Smith

Chapter7: Factoring

Section7.4: Factor Special Products

Problem 7.90TI: Factor: 9u2+87u+100 .

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Question

my teacher told me the answer was

4a⁷b⁶ because of the product of a power how can I tell the truth us there any laws in math please provide the law to correct her ty

GUIDED PRACTICE
Apply the laws of exponents in each.
1. (4a³b²)(-2a²b²)2

Product of a Power
Consider the expression 2'-2' using the definition of
exponents
2'-2 = (2-2-2)(2-2-2-2-2)=2
Thus, 2-2-2.
=23+5
=2"

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