+ -> 2le Li why iP instead of +]= 22 Why I P instead of -{e or°B???

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### Nuclear Reaction Explanation

In the illustrated image, we have a nuclear reaction equation that needs to be balanced and understood. The equation provided is:

\[
\begin{array}{c}
^{7}_{3}\text{Li} + ? \rightarrow ^{4}_{2}\text{He} \\
\\
\Rightarrow \quad ^{7}_{3}\text{Li} + ^{1}_{1}\text{P} \rightarrow 2 \cdot ^{4}_{2}\text{He} \\
\end{array}
\]

**Questions asked:**
1. Why \(^{1}_{1}\text{P}\) instead of \(^{3+ [ ? ] = 2} \)?
2. Why \(^{1}_{1}\text{P}\) instead of \(^{-1}_{0}\text{e}\) or \(^{-1}_{1}\text{B}\)???

**Detailed Explanation:**

The reaction explores how Lithium (\( ^{7}_{3}\text{Li} \)) combines with an unknown particle to form Helium (\(^{4}_{2}\text{He}\)).

Through analysis:
1. On the left side of the reaction, Lithium (\( ^{7}_{3}\text{Li} \)) has a mass number of 7 and an atomic number of 3.
2. On the right side, Helium (\(^{4}_{2}\text{He}\)) has a mass number of 4 and an atomic number of 2.

To balance the equation:
- The mass number on the left must equal the mass number on the right.
- Similarly, the atomic number on the left must equal the atomic number on the right.

From the corrected equation: 
\[
^{7}_{3}\text{Li} + ^{1}_{1}\text{P} \rightarrow 2 \cdot ^{4}_{2}\text{He}
\]

A proton (\(^{1}_{1}\text{P}\)) with a mass number of 1 and an atomic number of 1 is added to balance the equation.

### Graphs and Diagrams

In the image:
- Highlighted elements represent clarified parts of equations.
- Circles and arrows direct focus to balance aspects of nuclear reactions.

_For educational purposes, always ensure atomic numbers and mass numbers are balanced in nuclear equations._
Transcribed Image Text:### Nuclear Reaction Explanation In the illustrated image, we have a nuclear reaction equation that needs to be balanced and understood. The equation provided is: \[ \begin{array}{c} ^{7}_{3}\text{Li} + ? \rightarrow ^{4}_{2}\text{He} \\ \\ \Rightarrow \quad ^{7}_{3}\text{Li} + ^{1}_{1}\text{P} \rightarrow 2 \cdot ^{4}_{2}\text{He} \\ \end{array} \] **Questions asked:** 1. Why \(^{1}_{1}\text{P}\) instead of \(^{3+ [ ? ] = 2} \)? 2. Why \(^{1}_{1}\text{P}\) instead of \(^{-1}_{0}\text{e}\) or \(^{-1}_{1}\text{B}\)??? **Detailed Explanation:** The reaction explores how Lithium (\( ^{7}_{3}\text{Li} \)) combines with an unknown particle to form Helium (\(^{4}_{2}\text{He}\)). Through analysis: 1. On the left side of the reaction, Lithium (\( ^{7}_{3}\text{Li} \)) has a mass number of 7 and an atomic number of 3. 2. On the right side, Helium (\(^{4}_{2}\text{He}\)) has a mass number of 4 and an atomic number of 2. To balance the equation: - The mass number on the left must equal the mass number on the right. - Similarly, the atomic number on the left must equal the atomic number on the right. From the corrected equation: \[ ^{7}_{3}\text{Li} + ^{1}_{1}\text{P} \rightarrow 2 \cdot ^{4}_{2}\text{He} \] A proton (\(^{1}_{1}\text{P}\)) with a mass number of 1 and an atomic number of 1 is added to balance the equation. ### Graphs and Diagrams In the image: - Highlighted elements represent clarified parts of equations. - Circles and arrows direct focus to balance aspects of nuclear reactions. _For educational purposes, always ensure atomic numbers and mass numbers are balanced in nuclear equations._
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